问题

There is a dictionary object named my_dic.

my_dic = {'name': 'tom'}
print(f"The name is {my_dic.get('name')}")

In case my_dic is None, there will be an expected exception as 'NoneType' object has no attribute 'get'.

How to make one line code to get None in case my_dic is None, otherwise return by get().

Thanks.

my_dic = {'name': 'tom'}
print(f"The name is {my_dic.get('name')}")

答案1

得分: 1

您可以使用条件表达式来处理 `my_dic` 为 `None` 的情况。

```python
>>> my_dic = None
>>> print(f"名字是 {my_dic.get('name') if my_dic else None}")
名字是 None
>>> print(f"名字是 {None if my_dic is None else my_dic.get('name')}")
名字是 None

<details>
<summary>英文:</summary>

You might use a conditional expression to handle the case where `my_dic` is `None`.

>>> my_dic = None
>>> print(f"The name is {my_dic.get('name') if my_dic else None}")
The name is None
>>> print(f"The name is {None if my_dic is None else my_dic.get('name')}")
The name is None

</details>



# 答案2
**得分**: 1

my_dic = {'name': 'tom'} # 返回 name
# my_dic = None # 如果 my_dic 为 None，则返回 None
print(f"The name is {my_dic.get('name')}" if my_dic is not None else None)

<details>
<summary>英文:</summary>

    my_dic = {&#39;name&#39;: &#39;tom&#39;} # return name 
    # my_dic = None # return None if my_dic is None
    print(f&quot;The name is {my_dic.get(&#39;name&#39;)}&quot; if my_dic is not None else None)

</details>