How do I round the decimals to one digit in python?

I have written a code using which I have to duplicate a statement 100 times. In that, the variable "degrees" has to be iterated by 3.6. Instead of getting a decimal number with 1 decimal digit, I get something like this:

95%{background-color: linear-gradient(342.0000000000002deg, red, blue)}
96%{background-color: linear-gradient(345.60000000000025deg, red, blue)}
97%{background-color: linear-gradient(349.2000000000003deg, red, blue)}
98%{background-color: linear-gradient(352.8000000000003deg, red, blue)}

Here is my code:

degrees = 0
percent = 0

for i in range(101):
    print(str(percent) + "%{background-color: linear-gradient(" + str(degrees) + "deg, red, blue)}")
    percent += 1
    degrees += 3.6

I want the code to return the result with one decimal point.

you can use f-format string like this

degrees = 0
percent = 0

for i in range(101):
    print(f"{percent}%{{background-color: linear-gradient({degrees:.1f}deg, red, blue)}}")
    percent += 1
    degrees += 3.6

the output is

0%{background-color: linear-gradient(0.0deg, red, blue)}
1%{background-color: linear-gradient(3.6deg, red, blue)}
2%{background-color: linear-gradient(7.2deg, red, blue)}
3%{background-color: linear-gradient(10.8deg, red, blue)}
4%{background-color: linear-gradient(14.4deg, red, blue)}
5%{background-color: linear-gradient(18.0deg, red, blue)}
6%{background-color: linear-gradient(21.6deg, red, blue)}
7%{background-color: linear-gradient(25.2deg, red, blue)}
.......

You can use round(number, number digit)

for i in range(101):
    print(str(percent) + "%{background-color: linear-gradient(" + str(round(degrees,1)) + "deg, red, blue)}")

If your decimal number is strictly superior to 5, it will round to the next (ceil) whole number, otherwise it will round off to floor (floor).

print(round(342.14,1)) # 342.1
print(round(342.15,1)) # 342.1
print(round(342.16,1)) # 342.2