How to use awk to prepend as string AND append the substring found after the last occurance of "/" for each line in a file

I have a file myfile.sh like this:

tests/test1
tests/test2
tests/test3

I would like to do 2 things with this file:

1. prepend each line with "abc " string
2. append each line with whatever is found after the last occurrence of "/" on that line

So, my new file would need to look like:

abc tests/test1 test1
abc tests/test2 test2
abc tests/test3 test3

So far I am able to do #1 above and I am able to find the strings after the last occurrence of "/" on each line. I am doing this on Windows using GitBash, hence I use double quotes instead of single quotes:

awk "{print \"abc \" $0}" myfile.txt> mynewfile.txt

,this prepends each line with string "abc ".

awk -F/ "{print $NF}" myfile.txt> mynewfile.txt

, this finds string after the last occurrence of "/" on each line.

So, that is all good but I don't know how to do #2 to get to the desired file

You may use this awk command to print a static string as first column and using / as FS print last column:

awk -F/ 'NF {print "abc", $0, $NF}' file
abc tests/test1 test1
abc tests/test2 test2
abc tests/test3 test3

I have used NF as condition (to do it only for non-empty lines).

OP has to use " around awk command on Windows, so here it is:

# for Windows / DOS systems
awk -F/ "NF {print \"abc\", $0, $NF}" file
# for Unix based system
awk -F/ "NF {print \"abc\", $0, $NF}" file

As suggested by Ed, better to save awk script in a file and use that as awk script to avoid quotes escaping:

cat script.awk
NF {print "abc", $0, $NF}
awk -F/ -f script.awk file

Alternatively here is a sed command to do the same:

sed -E "s~.*/(.*)~abc & \\1~" file