英文:
How to implement explode functionality in Snowpark(Python) dataframe without using the explode() function?
问题
我正在使用Snowpark(Python)工作,并且正在使用snowflake-snowpark-python库的版本1.0.0。我有一个版本约束,因此不能升级。在这个版本中,不支持explode()函数。
如何在不使用explode()函数的情况下使用Snowpark Dataframe来实现相同的功能?我只有一个需要展开的列。
我的数据框(df)看起来像这样:
df = session.create_dataframe(["rest_of_the_row", ["A|B|C"]], schema=["record", "product_code"])
我的期望输出是:
+----------------+------------+
| record |product_code|
+----------------+------------+
| rest_of_the_row| A |
| rest_of_the_row| B |
| rest_of_the_row| C |
+----------------+------------+
我还会根据product_code进行进一步的聚合。请建议如何使用我自己的explode()实现这个目标?
英文:
I am working in Snowpark (Python), and I am using snowflake-snowpark-python library version 1.0.0. I have a version constraint, and hence cant upgrade. In this version, the function explode() is not supported.
How can I implement the same functionality using Snowpark Dataframe, without actually using explode() function? I have only one column that needs to be exploded.
My df looks like this:
df = session.create_dataframe(["rest_of_the_row",["A|B|C"]],schema=["record",product_code"])
My expected output is:
+----------------+------------+
| record |product_code|
+----------------+------------+
| rest_of_the_row| A |
| rest_of_the_row| B |
| rest_of_the_row| C |
+----------------+------------+
I am further doing aggregations based on product_code.
Please suggest, how can I achieve this with my own implementation of explode() ?
答案1
得分: 0
我无法使您的 df
语句工作,所以您可能需要纠正它。假设这是您的数据样式:
df = session.create_dataframe([{"record": "rest_of_the_row", "product_code": "A|B|C"}])
df.show()
------------------------------------
|"RECORD" |"PRODUCT_CODE" |
------------------------------------
|rest_of_the_row |A|B|C |
------------------------------------
然后您可以使用 split_to_table
来处理:
from snowflake.snowpark import functions as F
df.join_table_function("split_to_table", df['product_code'], F.lit("|")) \
.select(F.col("RECORD"), F.col("VALUE").alias("PRODUCT_CODE")) \
.show()
explode
接受数组或映射(对象)类型的输入,而您的输入是一个包含分隔符的字符串,所以我认为 explode
在您的情况下不会起作用。
英文:
I couldn't get your df
statement to work so you may want to correct it. Assuming this is what your data looks like:
df = session.create_dataframe([{"record": "rest_of_the_row","product_code": "A|B|C"}])
df.show()
------------------------------------
|"RECORD" |"PRODUCT_CODE" |
------------------------------------
|rest_of_the_row |A|B|C |
------------------------------------
Then you can use split_to_table
for this:
from snowflake.snowpark import functions as F
df.join_table_function("split_to_table", df['product_code'], F.lit("|")) \
.select(F.col("RECORD"), F.col("VALUE").alias("PRODUCT_CODE")) \
.show()
Explode takes an ARRAY or MAP (OBJECT) type as input, where as your input is a delimited string, so I don't think explode
would work in your case anyway.
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