英文:
Iterator with find() in c++
问题
我想知道当我使用find()命令时，如何获取结果的位置。
我的代码包含了以下命令：
vector<int>::iterator result = find(list_of_number.begin(), list_of_number.end(), number_need_to_find);cout << result;
但它给我返回了以下错误：
错误: 从类型 'std::vector<int>::iterator' 到类型 'int' 的无效转换57 | cout << (int)result;
英文:
I want to know how to get the position of the result when I use the find() command.
My code have the command:
vector<int>::iterator result = find(list_of_number.begin(), list_of_number.end(), number_need_to_find);cout << result;
And it give me the error as follow:
error: invalid cast from type 'std::vector<int>::iterator' to type 'int'57 | cout << (int)result;| ^~~~~~~~~~~
答案1
得分: 2
你的做法有问题。std::find 返回指向找到的元素的迭代器，如果未找到，则返回尾迭代器。因此，在使用迭代器 result 之前需要进行检查。
其次，这行代码：
std::cout << result;
尝试打印迭代器本身。你应该改为检查迭代器是否等于 list_of_number.end()，如果相等，然后使用 std::distance 来找到在 list_of_number 中找到的元素的位置。
#include <iterator> // std::distanceint main(){std::vector<int> list_of_number{1, 2, 3, 4};// 自 C++17 起支持 init-statementif (auto iter = std::find(list_of_number.cbegin(), list_of_number.cend(), 3); // 使用 std::find 查找元素iter != list_of_number.cend()) // 如果找到（即 iter 不是尾迭代器）{std::cout << std::distance(list_of_number.cbegin(), iter); // 使用 std::distance 找到位置}else{std::cout << "未找到\n";}}
英文:
You are doing it wrong. The std::find returns the iterator pointing to the element if it has been found, otherwise, it returns the end iterator. Therefore a check needs to be done prior to using the iterator result.
Secondly, the
std::cout << result;
trying to print the iterator itself. You should have instead checked the iterator for list_of_number.end() and (if found) use std::distance to find the position of the found element in the list_of_number.
#include <iterator> // std::distanceint main(){std::vector<int> list_of_number{1, 2, 3, 4};// if init-statement since C++17if (auto iter = std::find(list_of_number.cbegin(), list_of_number.cend(), 3); // find the element using std::finditer != list_of_number.cend()) // if found (i.e. iter is not the end of vector iterator){std::cout << std::distance(list_of_number.cbegin(), iter); // use std::distance for finding the position}else{std::cout << "Not found\n";}}
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