英文:
dataframe replace() is not working inside function
问题
这个问题可能是因为在函数内部使用了 dfnx.replace({s,c},inplace=True)，其中s和c是两个字符串，但它们应该是两个单独的参数，而不是一个字典键值对。你可以尝试修改函数的相应部分如下：
dfnx.replace(s, c, inplace=True)
这样应该能够正确地替换字符串中的空格。如果仍然存在问题，请确保在函数内部处理数据框时，没有对原始数据框进行不必要的修改，以免影响函数的其他部分。
英文:
I was replacing some strings (removing whitespaces) inside multiple dataframes manually, then I decided to centralize this code inside a function as follows (the print statements are just for debugging):
def merge_multiword_teams(dfnx,team_lst):
print(dfnx[dfnx['team'].str.contains('lazer')])
for s in team_lst:
c=s.replace(' ','')
print(s + c)
dfnx.replace({s,c},inplace=True)
print(dfnx[dfnx['team'].str.contains('lazer')])
return dfnx
then calling it
df = merge_multiword_teams(df,['Trail Blazers'])
the print statement shows that the whitespaces were not replaced
team W L W/L% GB PS/G PA/G SRS year
17 Portland Trail Blazers 49 33 0.598 16.0 105.6 103.0 2.6 2018
52 Portland Trail Blazers 41 41 0.5 26.0 107.9 108.5 -0.23 2017
79 Portland Trail Blazers 44 38 0.537 29.0 105.1 104.3 0.98 2016
109 Portland Trail Blazers 51 31 .622 102.8 98.6 4.41 2015
146 Portland Trail Blazers 54 28 .659 5.0 106.7 102.8 4.44 2014
Trail BlazersTrailBlazers
team W L W/L% GB PS/G PA/G SRS year
17 Portland Trail Blazers 49 33 0.598 16.0 105.6 103.0 2.6 2018
52 Portland Trail Blazers 41 41 0.5 26.0 107.9 108.5 -0.23 2017
79 Portland Trail Blazers 44 38 0.537 29.0 105.1 104.3 0.98 2016
109 Portland Trail Blazers 51 31 .622 102.8 98.6 4.41 2015
146 Portland Trail Blazers 54 28 .659 5.0 106.7 102.8 4.44 2014
what can be wrong with this approach ? given that moving the replace statement outside the function works perfectly
答案1
得分: 0
问题是你把s和c放在了一个集合中，但我认为你可能想把它们作为字典（{s:c}）。
英文:
The problem is that you've put s and c as a set when I think you meant it as a dict ({s:c})
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论