Where is the data string located in this disassembly?

I am going through the OS-dev book by Nick Blundell and I am disassembling the code in section 5.1.4.

Specifically, I have this c code stored in string.c:

void my_function()
{
    char* str = "Hello";
}

I compile it in 32-bit mode (since I am on 64-bit linux) this way:

gcc -ffreestanding -fno-pie -m32 -c string.c -o string.o

Linking step:

ld -m elf_i386 -o string.bin -Ttext 0x0 --oformat binary string.o

And disassembly:

ndisasm -b 32 string.bin > string.dis

And here is my result:

00000000  55                push ebp
00000001  89E5              mov ebp,esp
00000003  83EC10            sub esp,byte +0x10
00000006  C745FC00100000    mov dword [ebp-0x4],0x1000
0000000D  90                nop
0000000E  C9                leave
0000000F  C3                ret

I see that the compiler is allocating 16-bytes on the third line but I don't see where the "hello" string is located. I especially don't understand what happens at the 4th line.

Any help would be appreciated.

0x1000

Don't look for strings in the code segment. That's not where they are. The only instruction that is not part of the prologue or epilogue is mov dword [ebp-0x4],0x1000; which is clearly setting the local variable str to 0x1000. And we know that str points to the string.

Strings aren't in the text segment. They're in the rodata segment. Did you omit the rodata segment on linking?

(You compiled at -O0. Thus the dead code variable assignment was not removed.)