$a1 = [a,b];
$a2 = [a,c];
$a3 = [d,e];
$a4 = [d,f];
我知道使用`array_intersect()`函数可以找到数组之间的共同元素。
所以在这种情况下，我们将执行`array_intersect($a1,$a2,$a3,$a4)`，这将返回一个空数组，因为这4个数组之间没有共同的元素。
如果发生这种情况，我想在所有其他可能的3个数组组合上执行`array_intersect()`。
例如
```php
array_intersect($a1,$a2,$a3);  
array_intersect($a1,$a2,$a4);
array_intersect($a1,$a3,$a4);
array_intersect($a2,$a3,$a4);
array_intersect($a2,$a4,$a1);
array_intersect($a2,$a3,$a1);
array_intersect($a2,$a3,$a1);

array_intersect($a1,$a2);
array_intersect($a2,$a3);

$empty_array = [];
array_push($empty_array,$a1,$a2,$a3,$a4);
$arrayCount = count($empty_array);

<details>
<summary>英文:</summary>

I know using `array_intersect()` function we can find common element between the arrays
So in this case we will do `array_intersect($a1,$a2,$a3,$a4)`, this will return empty array
since there is no common element between the 4 arrays.
If this is happens I want to perform `array_intersect()` on all other possible combinations of 3 arrays.
For example

and so on..
and if any of these fail to return common element, which it will in our case, I would now like to perform
`array_intersect()` on the other possible combinations of 2 arrays.
For example

and so on..
This would work if I knew the number of arrays that I am working with, but in my case the number of arrays
will be dynamic. So what I want to do is start with `array_intersect()` on all the arrays, and if the empty array is returned,I want to perfom it on all other possible combinations.
I know that I must first start with counting the number of arrays to work with.

After this I am stuck,don't even know if this is even right to begin with. Any help will be greatly appreciated.
</details>
# 答案1
**得分**: 0
```php
$input = [
  [ 'a', 'b' ],
  [ 'a', 'c' ],
  [ 'd', 'e' ],
  [ 'd', 'f' ]
];
$all = array_values(array_unique(array_merge(...$input)));
$result = [];
foreach ($all as $search) {
  $count = 0;
  foreach ($input as $subArray) {
    if (in_array($search, $subArray, true)) {
      $count++;
    }
  }
  $result[$count][] = $search;
}
krsort($result);
foreach ($result as $count => $found) {
  echo "Found $count time(s): " . implode(', ', $found) . "\n";
}

Found 2 time(s): a, d
Found 1 time(s): b, c, e, f

$input = [
  [ 'a', 'b' ],
  [ 'a', 'c' ],
  [ 'd', 'e', 'a' ],
  [ 'd', 'f', 'a' ]
];
...
Found 4 time(s): a
Found 2 time(s): d
Found 1 time(s): b, c, e, f