英文:
Error: Process finished with exit code 138 (interrupted by signal 10: SIGBUS)
问题
我正在学习C编程，我编写了一个函数，并想看看它是如何工作的。
以下是代码片段：
#include <stdio.h>
void squeeze(char s[], int c) {
int i, j;
for (i = j = 0; s[i] != '#include <stdio.h>
void squeeze(char s[], int c) {
int i, j;
for (i = j = 0; s[i] != '\0'; i++) {
if (s[i] != c)
s[j++] = s[i];
}
s[j] = '\0';
printf("Converted: %s", s);
}
int main() {
squeeze("abcdefghigk", 'c');
}
'; i++) {
if (s[i] != c)
s[j++] = s[i];
}
s[j] = '#include <stdio.h>
void squeeze(char s[], int c) {
int i, j;
for (i = j = 0; s[i] != '\0'; i++) {
if (s[i] != c)
s[j++] = s[i];
}
s[j] = '\0';
printf("Converted: %s", s);
}
int main() {
squeeze("abcdefghigk", 'c');
}
';
printf("Converted: %s", s);
}
int main() {
squeeze("abcdefghigk", 'c');
}
但是当我运行它时，收到了以下错误：
进程以退出码138（被信号10：SIGBUS中断）结束
我使用的是MacBook M1，OS 13.4，Clion C23标准。
期望的结果是：
abdefghigk
但终端中没有显示任何内容，我在传递参数时出错了吗？
我已经查看了这个问题，它看起来很相似，但我不太理解答案，有人能帮忙解释一下吗？
英文:
I'm learning C programming and I wrote a function and wanted to see how it work.
Here is the snippet:
#include <stdio.h>
void squeeze(char s[], int c) {
int i, j;
for (i = j = 0; s[i] != '#include <stdio.h>
void squeeze(char s[], int c) {
int i, j;
for (i = j = 0; s[i] != '\0'; i++) {
if (s[i] != c)
s[j++] = s[i];
}
s[j] = '\0';
printf("Converted: %s", s);
}
int main() {
squeeze("abcdefghigk", 'c');
}
'; i++) {
if (s[i] != c)
s[j++] = s[i];
}
s[j] = '#include <stdio.h>
void squeeze(char s[], int c) {
int i, j;
for (i = j = 0; s[i] != '\0'; i++) {
if (s[i] != c)
s[j++] = s[i];
}
s[j] = '\0';
printf("Converted: %s", s);
}
int main() {
squeeze("abcdefghigk", 'c');
}
';
printf("Converted: %s", s);
}
int main() {
squeeze("abcdefghigk", 'c');
}
But when I run it, I received this:
Process finished with exit code 138 (interrupted by signal 10: SIGBUS)
I'm using macbook M1, OS13.4, Clion C23 standard.
Result expected:
abdefghigk
But nothing showed up in the terminal, did I make mistakes when pass the arguments?
I have reviewed this issue, it looks similiar, but I'm not quite understand the answers, could someone please help explain?
答案1
得分: 0
修改字符串字面量是未定义行为。
来自C标准（6.4.5 字符串字面量）
7 不确定这些数组是否不同，只要它们的元素具有适当的值即可。如果程序尝试修改这样的数组，则行为是未定义的。
使用数组来表示字符串：
char input[] = "abcdefghigk";
squeeze(input, 'c');
英文:
It is undefined behavior to modify a string literal.
From the C Standard (6.4.5 String literals)
> 7 It is unspecified whether these arrays are distinct provided their
> elements have the appropriate values. If the program attempts to
> modify such an array, the behavior is undefined.
Use an array for the string:
char input[] = "abcdefghigk";
squeeze(input, 'c');
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