英文:
How to create an isolated list of attributes for a python object?
问题
我有一个名为my_obj的Python对象，它有许多称为*attr1，attr2，attr3，...*的属性。这些属性表示为字符串。
我想按照以下模式创建这些属性的列表：
attr_list = [my_obj.attr1, my_obj.attr2, my_obj.attr3]
其中列表的每个元素都是一个对象，而不是一个字符串，使用一个循环，在循环中逐个添加元素。
在将它们连续附加到列表之前，我不知道如何将字符串转换为对象。
非常感谢你的帮助。
英文:
I have a python object called my_obj that has many attributes called attr1, attr2, attr3, .... represented as strings.
I would like to create a list of these attributes in the following pattern:
attr_list = [my_obj.attr1, my_obj.attr2, my_obj.attr3]
where each element of the list is an object rather than a string using a for loop in which elements are added one at a time.
I don't know how to convert strings into object before appending them to the list consecutively.
Your help is greatly appreciated.
答案1
得分: 1
有一个内置函数可以在Python 3中满足您的需求：getattr。
官方文档在此。
返回对象的命名属性的值。name必须是一个字符串。如果字符串是对象属性之一的名称，则结果是该属性的值。
我们可以使用getattr来解决您的问题：
attr_names = ["attr1", "attr2", "attr3"]
attr_list = []
for name in attr_names:
attr = getattr(my_obj, name)
attr_list.append(attr)
英文:
There is a built-in function that does what you need, off-the-shelf, in Python 3: getattr
Official doc here
> Return the value of the named attribute of object. name must be a
> string. If the string is the name of one of the object’s attributes,
> the result is the value of that attribute.
We could use getattr this way to tackle your problem:
attr_names = ["attr1", "attr2", "attr3"]
attr_list = []
for name in attr_names:
attr = getattr(my_obj, name)
attr_list.append(attr)
答案2
得分: 1
更清晰的方式可能是：
attr_list = [getattr(my_obj, name) for name in attr_names]
英文:
a cleaner way could be
attr_list=[getattr(my_obj,name)for name in attr_names]
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