将 int16_t 数组打包成多个 uint64_t

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英文:

Pack array of int16_t into multiple uint64_t

问题

以下是您提供的代码的翻译部分:

我有一个包含N个6个条目的数组

```cpp
const int16_t xzyabc[][6] PROGMEM = {
    {1, 2, 3, 4, 5, 6},
    {7, 8, 9, 10, 11, 12},
};

数组中的每个值都是int16_t数字

对于每四个int16_t,我想将它们打包到一个uint64_t中

我尝试了下面的代码。
void Telemetry::loop()
{
  const size_t numArrays = sizeof(xzyabc) / sizeof(xzyabc[0]);
  const size_t elementsPerArray = sizeof(xzyabc[0]) / sizeof(xzyabc[0][0]);
  const size_t elementsPerUint64 = 4;
  const size_t numUint64 = (numArrays * elementsPerArray + elementsPerUint64 - 1) / elementsPerUint64;

  uint64_t convertedArray[numUint64];

  for (size_t i = 0; i < numUint64; i++)
  {
    uint64_t value = 0;
    for (size_t j = 0; j < elementsPerUint64; j++)
    {
      size_t index = i * elementsPerUint64 + j;
      if (index < numArrays * elementsPerArray)
      {
        int16_t element = xzyabc[index / elementsPerArray][index % elementsPerArray];
        value |= static_cast<uint64_t>(element) << (16 * j);
      }
    }

    uint32_t upperPart = (uint32_t)(value >> 32);
    uint32_t lowerPart = (uint32_t)(value & 0xFFFFFFFF);
    Serial.print("Number: ");
    Serial.print(upperPart);
    Serial.print(lowerPart);
    Serial.println();

    convertedArray[i] = value;
  }

  callback(convertedArray, numUint64);
}

上面的代码的思想是遍历数组,对于每四个元素,将它们放入一个无符号整数中。

结果是:

Number: 262147131073
Number: 524295393221
Number: 786443655369

这些结果看起来对我来说是错误的,我尝试在NodeJS中解包它失败了。

我该如何修复这个问题?或者我做错了什么?


<details>
<summary>英文:</summary>


I have an array of N per 6 entries

const int16_t xzyabc[][6] PROGMEM = {
{1, 2, 3, 4, 5, 6},
{7, 8, 9, 10, 11, 12},
};

Each value in the array is an int16_t number.

For each four int16_t, I want to pack it onto a uint64_t.

I tried the code below.



void Telemetry::loop()
{
const size_t numArrays = sizeof(xzyabc) / sizeof(xzyabc[0]);
const size_t elementsPerArray = sizeof(xzyabc[0]) / sizeof(xzyabc[0][0]);
const size_t elementsPerUint64 = 4;
const size_t numUint64 = (numArrays * elementsPerArray + elementsPerUint64 - 1) / elementsPerUint64;

uint64_t convertedArray[numUint64];

for (size_t i = 0; i < numUint64; i++)
{
uint64_t value = 0;
for (size_t j = 0; j < elementsPerUint64; j++)
{
size_t index = i * elementsPerUint64 + j;
if (index < numArrays * elementsPerArray)
{
int16_t element = xzyabc[index / elementsPerArray][index % elementsPerArray];
value |= static_cast<uint64_t>(element) << (16 * j);
}
}

uint32_t parteSuperior = (uint32_t)(value &gt;&gt; 32);
uint32_t parteInferior = (uint32_t)(value &amp; 0xFFFFFFFF);
Serial.print(&quot;Number: &quot;);
Serial.print(parteSuperior);
Serial.print(parteInferior);
Serial.println();

convertedArray[i] = value;

}

callback(convertedArray, numUint64);
}


The idea of the code above is to iterate over the array and for each quadrupled, put it on a unsigned integer.

Results in:

Number: 262147131073
Number: 524295393221
Number: 786443655369


And they look wrong to me, I tried to unpack it on NodeJS and it failed.

How can I fix this? Or what I&#39;m doing wrong?

</details>


# 答案1
**得分**: 0

根据@Peter的建议,我最终使用了memcpy函数。

```cpp
uint64_t buffer[10]{0};

memcpy(buffer, xzyabc, sizeof(xzyabc));
英文:

As sugestion of @Peter, I ended using memcpy

uint64_t buffer[10]{0};

memcpy(buffer, xzyabc, sizeof(xzyabc));

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  • 本文由 发表于 2023年7月11日 00:50:09
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