英文:
'[[ 1' -gt 0 ']]' command not found, no special character shown by set -x
问题
当编写一个带有命令行参数的 bash 脚本时，我使用以下结构：
#!/bin/bash
set -e
extension=".fna.gz"
declare -A genomes_completeness
declare -a genomes
declare -a completeness
Help() {
echo "帮助信息"
}
# 设置变量的默认值并声明类型
foo=bar
if [ $# -eq 0 ]
then
Help
exit
fi
while [[ $# -gt 0 ]]
do
case $1 in
-f | --foo) foo="$2"
shift 2;;
-b | --bar) bar="$2"
shift 2;;
-h | --help) Help; exit;;
-* | --*) unknown="$1"; echo -e "未知选项: ${unknown}"; Help; exit 1;;
*) shift;;
esac
done
它运行良好，但当我执行没有参数或help标志的脚本时，检查帮助消息是否正确显示时，我遇到了以下错误：
bash /path/script.sh --help
+ extension=.fna.gz
+ declare -A genomes_completeness
+ declare -a genomes
+ declare -a completeness
+ '[' 1 -eq 0 ']'
+ '[[ 1' -gt 0 ']]'
/path/script.sh: 行 28: '[[ 1: 命令未找到
在寻找错误一段时间后，我只是复制粘贴了另一个脚本的 while ... 部分（仅该行），然后它就正常工作了。
我是在 Linux 上使用 nano 手工编写整个脚本的，所以我不知道是否插入了特殊字符（以及如何插入）。如果有特殊字符，它会在使用 set -x 时显示吗？还有其他可能导致这个错误的原因吗？
希望问题被正确提出。
英文:
When writing a bash script with command line arguments, I use the following structure :
#!/bin/bash
set -e
extension=".fna.gz"
declare -A genomes_completeness
declare -a genomes
declare -a completeness
Help() {
echo "help message"
}
#set default values of variables and declare types
foo=bar
if [ $# -eq 0 ]
then
Help
exit
fi
while [[ $# -gt 0 ]]
do
case $1 in
-f | --foo) foo="$2"
shift 2;;
-b | --bar) bar="$2"
shift 2;;
-h | --help) Help; exit;;
-* | --*) unknown="$1"; echo -e "Unknown option: ${unknown}"; Help; exit 1;;
*) shift;;
esac
done
It works well and I was writing another one but stumbled upon this error when checking if the Help message was correctly showing up when executing the script with no argument or the help flag:
bash /path/script.sh --help
+ extension=.fna.gz
+ declare -A genomes_completeness
+ declare -a genomes
+ declare -a completeness
+ '[' 1 -eq 0 ']'
+ '[[ 1' -gt 0 ']]'
/path/script.sh: line 28: [[ 1: command not found
After looking for an error for a while (hoho) I just copy-pasted the while ... (that line only) of another script and it then worked.
I wrote the script entirely by hand on linux with nano, so I have no idea if I inserted a special character (and how). If there was a special character would it show with set -x ? What are the other possible sources of that error ?
I hope the question is asked correctly.
答案1
得分: 0
输入<kbd>Compose</kbd><kbd>Space</kbd><kbd>Space</kbd>可能会插入一个不换行空格字符。通常，<kbd>AltGr</kbd>键被映射为"Compose"。
一些系统还会在您键入<kbd>Shift + Space</kbd>时插入一个不换行空格。
在Linux上，setxkbmap -print 可能会显示配置信息，man 7 xkeyboard-config 包含有关配置不换行空格输入的信息。
英文:
Typing <kbd>Compose</kbd><kbd>Space</kbd><kbd>Space</kbd> may insert a non-breaking space character. Commonly, the <kbd>AltGr</kbd> key is mapped to be "Compose".
Some systems also insert a non-breaking space if you type <kbd>Shift + Space</kbd>
On linux, setxkbmap -print may show configuration and man 7 xkeyboard-config has information about configuring non-breaking space input.
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