如何从gtsummary中的tbl_custom_summary访问当前的按类别分类?

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英文:

How to access the current by-category in a tbl_custom_summary from gtsummary?

问题

我想创建一个定制的gtsummary表格,在这个表格中,我需要访问由“by”分组的组中的病例数量。

例如,我想计算按治疗分组的每个阶段的患者响应比例。
目前,我使用以下方法来访问治疗组:

temp_drugname = pull(data %>% select(trt) %>% distinct())

只有在治疗组中至少有一个患者具有当前阶段时,这才有效。
如果有一个阶段没有分配给任何患者,我找不到计算正确总数的方法。

在下面的示例中,我删除了组A中患有1期癌症的病例。总数应为21,而不是54,以便稍后正确计算置信区间。

如何从gtsummary中的tbl_custom_summary访问当前的按类别分类?

library(gtsummary)
library(tidyverse)

my_ratio_summary = function (numerator, na.rm = TRUE, conf.level = 0.95) 
{
  function(data, full_data, ...) {
    temp_drugname = pull(data %>% select(trt) %>% distinct())
    if(length(temp_drugname) > 0){
      druggroup_data = full_data %>% filter(trt == temp_drugname)
    }
    else {
      druggroup_data = full_data
    }
    num <- sum(data[[numerator]], na.rm = na.rm)
    denom <- sum(druggroup_data[[numerator]], na.rm = na.rm)
    ratio <- num/denom

    dplyr::tibble(num = num, denom = denom, ratio = ratio)
  }
}

trial %>%
  filter(!(trt == 'Drug A' & stage == 'T1')) %>%
  tbl_custom_summary(
    include = c("stage"),
    by = "trt",
    stat_fns = ~ my_ratio_summary("response"),
    statistic = ~ "{ratio}%, {num}/{denom}",
    digits = ~ c(style_percent, 0, 0)
  )

<details>
<summary>英文:</summary>

I would like to create a customized gtsummary table, where I have to access the number of cases in that group resulting by `by`.

For example, I would like to calculate the proportion of patients with a response per stage grouped by treatment. 
Currently I use this workaround, to access the treatment group:

    temp_drugname = pull(data%&gt;%select(trt)%&gt;%distinct())

This works only, if there is at least one patient with the current stage in the treatment group.
If there is a stage without patients assigned to it, I can&#39;t find a way to calculate the correct total.

In the example below, I deleted the cases in group A with stage 1 cancer. The total should be 21, not 54, in order to later-on calculate confidence intervals correctly.

[![example with wrong total][1]][1]

library(gtsummary)
library(tidyverse)

my_ratio_summary = function (numerator, na.rm = TRUE, conf.level = 0.95)
{
function(data, full_data, ...) {
temp_drugname = pull(data%>%select(trt)%>%distinct())
if(length(temp_drugname) > 0){
druggroup_data = full_data%>%filter(trt == temp_drugname)
}
else {
druggroup_data = full_data
}
num <- sum(data[[numerator]], na.rm = na.rm)
denom <- sum(druggroup_data[[numerator]], na.rm = na.rm)
ratio <- num/denom

dplyr::tibble(num = num, denom = denom, ratio = ratio)

}
}

trial %>%
filter(!(trt == 'Drug A' & stage == 'T1'))%>%
tbl_custom_summary(
include = c("stage"),
by = "trt",
stat_fns = ~ my_ratio_summary("response"),
statistic = ~"{ratio}%, {num}/{denom}",
digits = ~ c(style_percent, 0, 0)
)


  [1]: https://i.stack.imgur.com/EUcHX.jpg

</details>


# 答案1
**得分**: 0

一个选择是使用通过`...`传递给自定义函数的附加参数,例如第一个元素是一个包含有关当前分组信息的`tibble`,可以用于筛选`full_data`,我使用了`semi_join`。即使`data`不包含任何观察值,这也可以正常工作。

在下面的代码中,我添加了一个`print`语句来显示`...`的内容:

```r
library(gtsummary)
library(tidyverse)

my_ratio_summary <- function(numerator, na.rm = TRUE, conf.level = 0.95) {
  function(data, full_data, ...) {
    
    dots <- list(...)
    
    # 仅添加以打印`dots`的内容
    print(dots)
    
    druggroup_data <- full_data %>% semi_join(dots[[1]], by = dots$by)
    
    num <- sum(data[[numerator]], na.rm = na.rm)
    denom <- sum(druggroup_data[[numerator]], na.rm = na.rm)
    ratio <- num / denom

    dplyr::tibble(num = num, denom = denom, ratio = ratio)
  }
}

trial %>%
  filter(!(trt == "Drug A" & stage == "T1")) %>%
  tbl_custom_summary(
    include = c("stage"),
    by = "trt",
    stat_fns = ~ my_ratio_summary("response"),
    statistic = ~"{ratio}%, {num}/{denom}",
    digits = ~ c(style_percent, 0, 0)
  )

如何从gtsummary中的tbl_custom_summary访问当前的按类别分类?


[1]: https://i.stack.imgur.com/yzP0t.png

<details>
<summary>英文:</summary>

One option would be to use the additional arguments passed to the custom function via `...`, e.g. the first element is a `tibble` which contains the info about the current groups which can be used to filter `full_data` for which I use a `semi_join`. This works even if `data` does not contain any observations. 

In the code below I added a `print` statement to show the content of `...`:

``` r
library(gtsummary)
library(tidyverse)

my_ratio_summary &lt;- function(numerator, na.rm = TRUE, conf.level = 0.95) {
  function(data, full_data, ...) {
    
    dots &lt;- list(...)
    
    # Only added to print the content of `dots`
    print(dots)
    
    druggroup_data &lt;- full_data %&gt;% semi_join(dots[[1]], by = dots$by)
    
    num &lt;- sum(data[[numerator]], na.rm = na.rm)
    denom &lt;- sum(druggroup_data[[numerator]], na.rm = na.rm)
    ratio &lt;- num / denom

    dplyr::tibble(num = num, denom = denom, ratio = ratio)
  }
}

trial %&gt;%
  filter(!(trt == &quot;Drug A&quot; &amp; stage == &quot;T1&quot;)) %&gt;%
  tbl_custom_summary(
    include = c(&quot;stage&quot;),
    by = &quot;trt&quot;,
    stat_fns = ~ my_ratio_summary(&quot;response&quot;),
    statistic = ~&quot;{ratio}%, {num}/{denom}&quot;,
    digits = ~ c(style_percent, 0, 0)
  )
#&gt; [[1]]
#&gt; # A tibble: 1 &#215; 2
#&gt;   trt    stage
#&gt;   &lt;chr&gt;  &lt;fct&gt;
#&gt; 1 Drug A T1   
#&gt; 
#&gt; $variable
#&gt; [1] &quot;stage&quot;
#&gt; 
#&gt; $by
#&gt; [1] &quot;trt&quot;
#&gt; 
#&gt; $type
#&gt; [1] &quot;categorical&quot;
#&gt; 
#&gt; $stat_display
#&gt; [1] &quot;{ratio}%, {num}/{denom}&quot;

...

如何从gtsummary中的tbl_custom_summary访问当前的按类别分类?

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  • 本文由 发表于 2023年7月11日 00:32:03
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