org.json.JSONException 在尝试解析复杂的 JSON 子部分时发生

huangapple
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英文:

org.json.JSONException when trying to parse complex JSON subsection

问题

  1. // 获取为jsonString后
  2. JSONObject productsJsonObject = (JSONObject) new JSONTokener(jsonString).nextValue();
  4. // 这将记录上面列出的正确的JSON
  5. logger.info("productsJsonObject = {}", productsJsonObject); 
  7. // 异常发生在这里:
  8. JSONObject productTypeJsonSection = (JSONObject) productsJsonObject.get("productTypes");

抛出以下异常:

  1. org.json.JSONException: 未找到 JSONObject["productTypes"].
  2.         at org.json.JSONObject.get(JSONObject.java:422) ~[json-NOT_KNOWN.jar:?]
英文:

Am facing impediments when using Java 1.8 and the org.json lib to marshal & parse a complex JSON object...

JSON dependency:

  1. <dependency>
  2.     <groupId>org.json</groupId>
  3.     <artifactId>json</artifactId>
  4.     <version>NOT_KNOWN</version>
  5. </dependency>

JSON response payload:

  1. {
  2. 	"products": {
  3. 		"productTypes": {
  4. 			"storeId": "abc123"
  5. 			"names": [
  6. 				"sku": "123",
  7. 				"prices": {
  8. 					"salesTax": .2,
  9. 					"wholeSalePrice": 5,
  10. 					"retailPrice": 10
  11. 				}
  12. 			]
  14. 		}
  15. 	}
  16. }
  1. // After obtaining as a jsonString
  2. JSONObject productsJsonObject = (JSONObject) new JSONTokener(jsonString).nextValue();
  4. // This logs the correct the JSON listed above
  5. logger.info("productsJsonObject = {}", productsJsonObject); 
  7. // Exception happens here:
  8. JSONObject productTypeJsonSection = (JSONObject) productsJsonObject.get("productTypes");

This exception is thrown:

  1. org.json.JSONException: JSONObject["productTypes"] not found.
  2.         at org.json.JSONObject.get(JSONObject.java:422) ~[json-NOT_KNOWN.jar:?]

答案1

得分: 2

首先，当我在你问题中提供的JSON字符串上运行你的代码时，我得到了一个错误：

  1. Exception in thread "main" org.json.JSONException: Expected a ',' or ']' at 128 [character 26 line 6]

正如@TimMoore在他的评论中所写的：

名为 productsJsonObject 的对象实际上是包含产品对象的顶级对象。

你有一个没有命名的JSON对象，其中包含一个名为 products 的成员。因此，在你执行以下操作后：

  1. JSONObject productsJsonObject = (JSONObject) new JSONTokener(jsonString).nextValue();

你需要执行以下操作：

  1. productsJsonObject = (JSONObject) productsJsonObject.get("products");

然后，你可以执行以下操作：

  1. JSONObject productTypesJsonObject = (JSONObject) productsJsonObject.get("productTypes");

以下是一个完整的示例，包括我对JSON字符串所做的更改，以克服上面提到的异常。

请注意，该代码使用了JDK 15中首次添加的文本块。

  1. import org.json.JSONObject;
  2. import org.json.JSONTokener;
  4. public class OrgJsonT {
  6.     public static void main(String[] args) {
  7.         String json = """
  8. {
  9.     "products": {
  10.         "productTypes": {
  11.             "storeId": "abc123",
  12.             "names": [
  13.                 {
  14.                     "sku": 123
  15.                 },
  16.                 {
  17.                     "prices": {
  18.                         "salesTax": .2,
  19.                         "wholeSalePrice": 5,
  20.                         "retailPrice": 10
  21.                     }
  22.                 }
  23.             ]
  24.         }
  25.     }
  26. }
  27. """;
  28.         JSONTokener jsonTokener = new JSONTokener(json);
  29.         JSONObject jsonObject = (JSONObject) jsonTokener.nextValue();
  30.         JSONObject productsJsonObject = (JSONObject) jsonObject.get("products");
  31.         JSONObject productTypesJsonObject = (JSONObject) productsJsonObject.get("productTypes");
  32.         System.out.println(productTypesJsonObject);
  33.     }
  34. }

运行上述代码会打印以下内容：

  1. {"names":[{"sku":123},{"prices":{"wholeSalePrice":5,"salesTax":".2","retailPrice":10}}],"storeId":"abc123"}
英文:

First of all, when I ran your code on the JSON string in your question, I got an error:

  1. Exception in thread "main" org.json.JSONException: Expected a ',' or ']' at 128 [character 26 line 6]

As @TimMoore wrote in his comment:
> The object named productsJsonObject is actually the top level object that contains the products object.

You have an unnamed JSON object that contains a single member named products. Hence after you do this:

  1. JSONObject productsJsonObject = (JSONObject) new JSONTokener(jsonString).nextValue();

you need to do this:

  1. productsJsonObject = (JSONObject) productsJsonObject.get("products");

Then you can do this:

  1. JSONObject productTypesJsonObject = (JSONObject) productsJsonObject.get("productTypes");

Here is a complete example – including changes I made to the JSON string in order to overcome the exception, above.

Note that the code uses text blocks which were first added in JDK 15.

  1. import org.json.JSONObject;
  2. import org.json.JSONTokener;
  4. public class OrgJsonT {
  6.     public static void main(String[] args) {
  7.         String json = """
  8. {
  9.     "products": {
  10.         "productTypes": {
  11.             "storeId": "abc123",
  12.             "names": [
  13.                 {
  14.                     "sku": 123
  15.                 },
  16.                 {
  17.                     "prices": {
  18.                         "salesTax": .2,
  19.                         "wholeSalePrice": 5,
  20.                         "retailPrice": 10
  21.                     }
  22.                 }
  23.             ]
  24.         }
  25.     }
  26. }
  27.                 """;
  28.         JSONTokener jsonTokener = new JSONTokener(json);
  29.         JSONObject jsonObject = (JSONObject) jsonTokener.nextValue();
  30.         JSONObject productsJsonObject = (JSONObject) jsonObject.get("products");
  31.         JSONObject productTypesJsonObject = (JSONObject) productsJsonObject.get("productTypes");
  32.         System.out.println(productTypesJsonObject);
  33.     }
  34. }

Running the above code prints the following:

  1. {"names":[{"sku":123},{"prices":{"wholeSalePrice":5,"salesTax":".2","retailPrice":10}}],"storeId":"abc123"}

huangapple
  • 本文由 发表于 2023年7月10日 18:00:22
  • 转载请务必保留本文链接：https://go.coder-hub.com/76652657.html
  • java
  • java-8
  • json
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