打印第一行，然后赋值给一个变量。

huangapple
go评论96阅读模式
英文:

Printing first line then assign to a variable

问题

  1. for a in soup.find_all('a', href=True):
  2.     if "/xxxxxx/xxxxxxxxxxxxx-" in a['href']:
  3.         x = ("https://www.unkown.com" + a['href'])
  4.         print(x[0])
  5.     else:
  6.         pass
  7.         
  8. my output:
  9. https://www.unkown.com/xxxxx/xxxxxxxxxx
  10. https://www.unkown.com/xxxxx/1xxxxxxxxx
  11. https://www.unkown.com/xxxxx/2xxxxxxxxx
  12. https://www.unkown.com/xxxxx/3xxxxxxxxx
英文: 
  1. for a in soup.find_all('a', href=True):
  2.     if "/xxxxxx/xxxxxxxxxxxxx-" in a['href']:
  3.         x = ("https://www.unkown.com" + a['href'])
  4.         print(x[0])
  5.     else:
  6.         pass
  7.         
  8. my output:
  9. https://www.unkown.com/xxxxx/xxxxxxxxxx
  10. https://www.unkown.com/xxxxx/1xxxxxxxxx
  11. https://www.unkown.com/xxxxx/2xxxxxxxxx
  12. https://www.unkown.com/xxxxx/3xxxxxxxxx

I want to print the first line by doing print(x[0]) I just print "h" the output is bunch of url's

答案1

得分: 1

如果您的输出 x 是：

  1. https://www.unkown.com/xxxxx/xxxxxxxxxx
  2. https://www.unkown.com/xxxxx/1xxxxxxxxx
  3. https://www.unkown.com/xxxxx/2xxxxxxxxx
  4. https://www.unkown.com/xxxxx/3xxxxxxxxx

您可以通过调用 x.split('\n')[0] 来访问第一行。

英文:

If your output x is :

  1. https://www.unkown.com/xxxxx/xxxxxxxxxx
  2. https://www.unkown.com/xxxxx/1xxxxxxxxx
  3. https://www.unkown.com/xxxxx/2xxxxxxxxx
  4. https://www.unkown.com/xxxxx/3xxxxxxxxx

You can access the first line by calling x.split('\n')[0].

答案2

得分: 0

在Python中，字符串索引（x[0]）返回该索引处的字符，而不是列表中的元素。在您的情况下，x是一个字符串，所以x[0]将返回'h'，即您的URL的第一个字符。

要仅打印第一个匹配的URL，您可以使用一个布尔标志。以下是一个示例：

  1. first_match_found = False
  3. for a in soup.find_all('a', href=True):
  4.     if "/xxxxxx/xxxxxxxxxxxxx-" in a['href'] and not first_match_found:
  5.         print("https://www.unkown.com" + a['href'])
  6.         first_match_found = True

此脚本将在找到第一个匹配后停止打印URL。

英文:

In Python, string indexing (x[0]) returns the character at that index, not an element from a list. In your case, x is a string, so x[0] will return 'h', the first character of your URL.

To print only the first matching URL, you can use a boolean flag. Here's an example:

  1. first_match_found = False
  3. for a in soup.find_all('a', href=True):
  4.     if "/xxxxxx/xxxxxxxxxxxxx-" in a['href'] and not first_match_found:
  5.         print("https://www.unkown.com" + a['href'])
  6.         first_match_found = True

This script will stop printing URLs after the first match.

huangapple
  • 本文由 发表于 2023年7月10日 17:47:58
  • 转载请务必保留本文链接：https://go.coder-hub.com/76652564.html
  • python
  • python-3.x
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