为什么这段代码一直运行 else? python3

huangapple
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英文:

Why does this code keep running else? python3

问题

  1. check = input("检查 x 还是 y。")
  3. while True:
  4.     print("输入是", check)
  5.     if check == "x":
  6.         print("跟随 x")
  7.         break
  8.     elif check == "y":
  9.         print("跟随 y")
  10.         break
  11.     else:
  12.         print("跟随其他")
  13.         break
  15. print("结束")
英文: 
  1. check = input("check for x or y. ")
  3. while True:
  4.     print("input was" , check)
  5.     if input == "x":
  6.         print("Following x")
  7.         break
  8.     elif input == "y":
  9.         print("Following y")
  10.         break
  11.     else:
  12.         print("Following else")
  13.         break
  15. print("end")

I am trying to run the if statement depending on the input but regardless of input it always goes to else.

答案1

得分: 2

你正在比较input函数，而不是调用input函数并从键盘读取输入的结果(check)。

  1. check = input("检查x还是y。")
  3. while True:
  4.     print("输入是", check)
  5.     if check == "x":
  6.         print("跟随x")
  7.         break
  8.     elif check == "y":
  9.         print("跟随y")
  10.         break
  11.     else:
  12.         print("跟随其他")
  13.         break
  15. print("结束")
英文:

You are comparing the input function, not the result (check) of calling the input function and reading the input from the keyboard

  1. check = input("check for x or y. ")
  3. while True:
  4.     print("input was" , check)
  5.     if check == "x":
  6.         print("Following x")
  7.         break
  8.     elif check == "y":
  9.         print("Following y")
  10.         break
  11.     else:
  12.         print("Following else")
  13.         break
  15. print("end")

huangapple
  • 本文由 发表于 2023年7月10日 17:00:07
  • 转载请务必保留本文链接：https://go.coder-hub.com/76652221.html
  • if-statement
  • python
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