英文:
Selecting a single element in D3 .join
问题
我有以下的代码，它使用mouseover和mouseout函数创建一系列点。然而，我无法弄清楚如何引用单个“point”实例 - 使用变量point会选择所有点：
settings.g.selectAll("node").data(positions).join(enter => {let point = enter.append("circle").attr("cx", d => d.x).attr("cy", d => d.y).attr("stroke-opacity", 0.5).on('mouseover', (d) => {pointMouseOver(d)point.attr("stroke-opacity", 1) //这会选择所有点，而不仅仅是一个}).on('mouseout', (d) => pointMouseOut(d))})
英文:
I have the following code which creates a series of points with mouseover and mouseout functions. However, I cannot figure out how to reference a single "point" instance - using the variable point selects all of them:
settings.g.selectAll("node").data(positions).join(enter => {let point=enter.append("circle").attr("cx", d => d.x).attr("cy", d => d.y).attr("stroke-opacity", 0.5).on('mouseover', (d)=> {pointMouseOver(d)point.attr("stroke-opacity", 1) //THIS SELECTS ALL POINTS, NOT JUST 1}).on('mouseout', (d)=>pointMouseOut(d))})
答案1
得分: 1
point变量是输入选择， 在你的情况下包含多个元素。
要获取选定的元素，请使用this或者，因为你使用了箭头函数：
.on('mouseover', (d, i, n) => {d3.select(n[i]).attr("stroke-opacity", 1)})
在最近版本的D3中，你可以在监听器中使用event.currentTarget：.on('mouseover', (event, d) => { ... })。
英文:
The point variable is the enter selection, which in your case contains several elements.
To get the selected element use this or, since you have an arrow function:
.on('mouseover', (d, i, n)=> {d3.select(n[i]).attr("stroke-opacity", 1)})
In recent versions of D3 you can use event.currentTarget in the listener: .on('mouseover', (event, d) => { ... }).
通过集体智慧和协作来改善编程学习和解决问题的方式。致力于成为全球开发者共同参与的知识库，让每个人都能够通过互相帮助和分享经验来进步。
评论