英文:
Deserialize response body with dynamic schema using Spring WebClient
问题
我正在使用Spring WebClient来向外部API发送请求。但是有一个端点在成功的HTTP请求时不返回统一的JSON。当它有数据返回时，我会得到以下JSON响应：
{
"String A": "d7e75c1d-71d1-4628-ad01-cd65a7aabd52",
"String B": "4a28c303-fb5c-4648-926e-fd2db1178838"
}
然而，当没有数据时，它会返回一个空的JSON数组：
[]
在这两种情况下，HTTP请求都以200响应代码完成。
以下是执行请求的代码：
public Map<String, UUID> getIdsByDisplayNames(List<String> displayNames) {
return webClient.get()
.uri(uriBuilder -> {
uriBuilder.path("/api/display-names/account-ids");
for (String displayName : displayNames) {
uriBuilder.queryParam("displayName[]", displayName);
}
return uriBuilder.build();
})
.retrieve()
.bodyToMono(new ParameterizedTypeReference<Map<String, UUID>>() {})
.block();
}
当响应体中有一个JSON对象时，它运行良好，但当端点返回一个空数组时，我会得到一个异常：
org.springframework.core.codec.DecodingException: JSON decoding error: Cannot deserialize value of type
java.util.LinkedHashMap<java.lang.String,java.util.UUID>from Array value (tokenJsonToken.START_ARRAY)
我该如何在我的代码中解决这个问题？
英文:
I'm using Spring WebClient to make requests to external API. But there's an endpoint that does not return a uniform json on successful HTTP request. When it has data to return I get a response with following json:
{
"String A": "d7e75c1d-71d1-4628-ad01-cd65a7aabd52",
"String B": "4a28c303-fb5c-4648-926e-fd2db1178838"
}
Howewer when there's nothing it returns an empty json array:
[]
In both cases HTTP request completes with 200 response code.
Here's my code that does a request:
public Map<String, UUID> getIdsByDisplayNames(List<String> displayNames) {
return webClient.get()
.uri(uriBuilder -> {
uriBuilder.path("/api/display-names/account-ids");
for (String displayName : displayNames) {
uriBuilder.queryParam("displayName[]", displayName);
}
return uriBuilder.build();
})
.retrieve()
.bodyToMono(new ParameterizedTypeReference<Map<String, UUID>>() {})
.block();
}
It works well when there's a json object in response body but when endpoint returns an empty array I get an exception:
> org.springframework.core.codec.DecodingException: JSON decoding error: Cannot deserialize value of type java.util.LinkedHashMap<java.lang.String,java.util.UUID> from Array value (token JsonToken.START_ARRAY)
How can I solve it in my code?
答案1
得分: 0
代替请求Map<String, UUID>，您可以请求JsonNode。
该类提供了一些方法isArray和isObject，用于确定响应是JSON对象还是JSON数组。
英文:
Instead of asking for a Map<String, UUID>, you could ask for a JsonNode.
This class provides some methods isArray and isObject to determine if the response is a JSON Object or a JSON Array.
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