英文:
Confusion with the output of the function str
问题
在Baystate医疗中心（位于美国春田）于1986年收集的birth.csv数据集具有以下格式
导入csv文件后（使用read.csv()和colClasses参数），str()函数的输出与head()函数不匹配。例如，列low的前6个值应该是0，但str()生成的示例输出显示它们为1
'data.frame': 189 obs. of 9 variables:$ low : Factor w/ 2 levels "0","1": 1 1 1 1 1 1 1 1 1 1 ... # 但它们应该是 0 0 0 0... 对吗？$ age : num 19 33 20 21 18 21 22 17 29 26 ...$ lwt : num 182 155 105 108 107 124 118 103 123 113 ...$ race : Factor w/ 3 levels "1","2","3": 2 3 1 1 1 3 1 3 1 1 ...$ smoke: Factor w/ 2 levels "0","1": 1 1 2 2 2 1 1 1 2 2 ...$ ptl : Factor w/ 2 levels "0","1": 1 1 1 1 1 1 1 1 1 1 ...$ ht : Factor w/ 2 levels "0","1": 1 1 1 1 1 1 1 1 1 1 ...$ ui : Factor w/ 2 levels "0","1": 2 1 1 2 2 1 1 1 1 1 ...$ ftv : Factor w/ 3 levels "0","1","2": 1 3 2 3 1 1 2 2 2 1 ...A data.frame: 6 × 9low age lwt race smoke ptl ht ui ftv<fct><dbl><dbl><fct><fct><fct><fct><fct><fct>1 0 19 182 2 0 0 0 1 02 0 33 155 3 0 0 0 0 23 0 20 105 1 1 0 0 0 14 0 21 108 1 1 0 0 1 25 0 18 107 1 1 0 0 1 06 0 21 124 3 0 0 0 0 0
请问有人能解释一下发生了什么吗？如果我为导入的数据集构建了一个逻辑模型，结果会是错误的吗？
英文:
The data set birth.csv collected at the Baystate Medical Center, Springfield, USA during 1986 has the following format
After I imported the csv file (using read.csv() with colClasses specification), the output of the function str() didn't match with that of the function head(). For example, the first 6 values of the column low were supposed to be 0 but the output sample generated by str() showed they were 1
'data.frame': 189 obs. of 9 variables:$ low : Factor w/ 2 levels "0","1": 1 1 1 1 1 1 1 1 1 1 ... # shouldn't they be 0 0 0 0... instead?$ age : num 19 33 20 21 18 21 22 17 29 26 ...$ lwt : num 182 155 105 108 107 124 118 103 123 113 ...$ race : Factor w/ 3 levels "1","2","3": 2 3 1 1 1 3 1 3 1 1 ...$ smoke: Factor w/ 2 levels "0","1": 1 1 2 2 2 1 1 1 2 2 ...$ ptl : Factor w/ 2 levels "0","1": 1 1 1 1 1 1 1 1 1 1 ...$ ht : Factor w/ 2 levels "0","1": 1 1 1 1 1 1 1 1 1 1 ...$ ui : Factor w/ 2 levels "0","1": 2 1 1 2 2 1 1 1 1 1 ...$ ftv : Factor w/ 3 levels "0","1","2": 1 3 2 3 1 1 2 2 2 1 ...A data.frame: 6 × 9low age lwt race smoke ptl ht ui ftv<fct><dbl><dbl><fct><fct><fct><fct><fct><fct>1 0 19 182 2 0 0 0 1 02 0 33 155 3 0 0 0 0 23 0 20 105 1 1 0 0 0 14 0 21 108 1 1 0 0 1 25 0 18 107 1 1 0 0 1 06 0 21 124 3 0 0 0 0 0
Could someone please explain what happened? If I built a logistic model for that imported dataset, would the result be wrong?
答案1
得分: 1
在R中，因子（即分类变量，在tibble列标签中表示为<fct>）内部存储为整数，其中1表示第一个水平（或类别），2表示第二个水平，以此类推，同时还有一个查找表将整数值映射到它们的标签/水平。
使用str()函数查看一些水平以及它们的整数值。大多数其他函数会打印标签，而不是整数值。
在你的情况下可能会有些混淆，因为你的标签是（字符类）整数，从0开始。为了更清晰的示例，让我们看一个标签为字母的因子：
x = factor(c("a", "b", "a", "c"))x# [1] a b a c# Levels: a b cstr(x)# Factor w/ 3 levels "a","b","c": 1 2 1 3
英文:
Factors (categorical variables, <fct> in the tibble column class labels) in R are stored internally as integers with 1 being the first level (or category), 2 the second level, etc., along with a lookup table mapping the integer values to their labels/levels.
str() a few of the levels and then the integer values. Most other functions print the labels, not the integer values.
It's extra confusing in your case because your labels are (character-class) integers starting at 0. For a somewhat clearer example, let's look at a factor with letters as the labels
x = factor(c("a", "b", "a", "c"))x# [1] a b a c# Levels: a b cstr(x)# Factor w/ 3 levels "a","b","c": 1 2 1 3
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