如何将 Prisma 模型作为通用基础存储库（baseRepository）的创建工作？

huangapple
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英文:

How to make prisma model work as generic for creating baseRepository?

问题

以下是翻译好的部分：

"The idea is I pass the model name to use crud operation for all tables :

  1. class BaseRepository{
  2.     db = prisma
  3.     async findAll(modelName: "user" | "post"){
  4.         return await this.prisma[modelName].findMany()
  5.     }
  6. }

The findMany doesn't work and returns typescript error and also when I tried to use findUnique or any other function they don't work also.. how I can make them work?"

英文:

The idea is I pass the model name to use crud operation for all tables :

  1. class BaseRepository{
  2. db = prisma
  3.     async  findAll(modelName: "user" | "post"){
  4.     return  await this.prisma[modelName].findMany()
  5.     }
  6. }

The findMany doesn't work and returns typescript error and also when I tried to use findUnique or any other function they don't work also.. how I can make them work?

答案1

得分: 1

使用 switch 的最简单方法：

  1. async findAll(modelName: 'user' | 'post') {
  2.   switch (modelName) {
  3.     case 'user':
  4.       return this.prisma.user.findMany();
  5.     case 'post':
  6.       return this.prisma.post.findMany();
  7.   }
  8. }
英文:

the easiest way use switch

  1. async findAll(modelName: 'user' | 'post') {
  2.   switch (modelName) {
  3.     case 'user':
  4.       return this.prisma.user.findMany();
  5.     case 'post':
  6.       return this.prisma.post.findMany();
  7.   }
  8. }

huangapple
  • 本文由 发表于 2023年7月7日 07:39:22
  • 转载请务必保留本文链接：https://go.coder-hub.com/76633115.html
  • express
  • node.js
  • prisma
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