How do I return a list of column values when the rows are the same for every other column in pandas?

I apologize if my question was unclear. I have a dataframe that contains these values:

As we can see, the first two rows contain the same data except for the 'Article' column. I want to write a code a that returns me a list/tuple that contains all the values of the 'Article' field that contain the same data. In this particular case the ideal output would be something like:

[('025-03-7579','025-03-2888')]

I have tried to use df.groupby('Article') to create two lists and compare them, returning a tuple whenever there was a match in articles but I have had no success.

Any feedback would be highly appreciated!

Group by all columns except Article and filter groups with duplicate values:

[tuple(gr['Article']) for _, gr in df.groupby(['Rating', 'UserName', 'ReviewDate', 'Score']) 
 if gr.index.size > 1]

[('025-03-7579', '025-03-2888')]

Did you try a groupby more similar to something like this

df1 =  df.groupby(["Rating","UserName","ReviewDate","Score"])["Article"].apply(list).reset_index()

Another possible solution:

df['Article'][df.duplicated(
    df.columns[df.columns != 'Article'], keep=False)].to_list()

Output:

['025-03-7579', '025-03-2888']

If a tuple per group is needed:

cols = df.columns[df.columns != 'Article']
(df[df.duplicated(cols, keep=False)]
 .groupby(cols.to_list())['Article'].agg(tuple).tolist())

Output:

[('025-03-7579', '025-03-2888')]