英文:
How to concatenete 2 String to base64 String
问题
You can concatenate two strings to a Base64 string like this:
const base64basic = "data:image/png;base64,";
const base64back = JSON.stringify(dataNew.base64Img);
const base64picture = base64basic.concat(base64back);
console.log(base64picture);
However, it seems there are " in the resulting string, which should not be there.
英文:
How can i concatenete 2 Strings to Base64 String?
Ive tried this:
const base64basic = "data:image/png;base64,";
const base64back = JSON.stringify(dataNew.base64Img);
const base64picture = base64basic.concat(base64back)
console.log(base64picture)
dataNew.base64Img is my Base64 String:
iVBORw0KGgoAAAANSUhEUgAAAEAAAAAwCAYAAAChS3wfAAAAAXNSR0IArs4c6QAAASFJREFUaEPtmsEOxCAIRAf3//94Ixu8CySkQbfTSw/VpLwOA2pljKFougTAZwJ2310i+6cqwBeKSgDSDkABcSL4ewCmPw+AJ05TwBTcrQAL3ksB1b081pMhlwOwIJwU8AAsddwOIPJfnZ5BAOYR15qgBe/JP4ITiCczHa1VIPWGDw86HkDkAV6ZzLAjgM5GKPOFqACnD1gm6rTKGcBMAaZA42owI1F6AD3Ab3RpgqwCtdUEyyDLIMtg364w+4AEgdc3QglGpSHHV4FSdInJBHB6GUx8xNIQKoAKOLwRKuk7MZkpwBRgCpy9FkikcWkIPYAeQA+gB1R+sCgZ0AmT200w2vCIIF1/LkAAwdEXFRAQYAqUjsak/y+xXg94PYBBBfwA5wWZJstGb8AAAAAASUVORK5CYII=
After concatenetion i get the output in console this:
data:image/png;base64,"iVBORw0KGgoAAAANSUhEUgAAAEAAAAAwCAYAAAChS3wfAAAAAXNSR0IArs4c6QAAASFJREFUaEPtmsEOxCAIRAf3//94Ixu8CySkQbfTSw/VpLwOA2pljKFougTAZwJ2310i+6cqwBeKSgDSDkABcSL4ewCmPw+AJ05TwBTcrQAL3ksB1b081pMhlwOwIJwU8AAsddwOIPJfnZ5BAOYR15qgBe/JP4ITiCczHa1VIPWGDw86HkDkAV6ZzLAjgM5GKPOFqACnD1gm6rTKGcBMAaZA42owI1F6AD3Ab3RpgqwCtdUEyyDLIMtg364w+4AEgdc3QglGpSHHV4FSdInJBHB6GUx8xNIQKoAKOLwRKuk7MZkpwBRgCpy9FkikcWkIPYAeQA+gB1R+sCgZ0AmT200w2vCIIF1/LkAAwdEXFRAQYAqUjsak/y+xXg94PYBBBfwA5wWZJstGb8AAAAAASUVORK5CYII="
There are " in the String, which should not there.
答案1
得分: 2
JSON.stringify会引用字符串，所以您不需要它：
const base64picture = "data:image/png;base64," + dataNew.base64Img;
console.log(base64picture);
英文:
JSON.stringify quotes string, so you don't need it:
const base64picture = "data:image/png;base64," + dataNew.base64Img;
console.log(base64picture);
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