英文:
Calculate min() and max() of each matrix column
问题
我使用以下矩阵：
dput(data) =
结构（c（269.643848985434，284.856715574861，278.687093704939，
242.00628682971，258.754844814539，257.241126745939，250.868861973286，
267.881099879742，266.277047023177，264.643696397543，283.306375294924，
278.137760534883，251.230201125145，264.389782398939，260.087893307209，
263.933225497603，284.947050362825，279.185155779123，262.722251042724，
284.903103709221，279.329203143716，256.589251384139，274.861293360591，
270.730307921767，233.265785723925，249.657887518406，247.94396802783，
264.665669724345，284.124271348119，278.701742589474，0，0，0
），dim = c（3L，11L），dimnames = list(NULL，c（& quot; & quot;，& quot; & quot;，& quot; & quot;，& quot; & quot;，
& quot; & quot;，& quot; & quot;，& quot; & quot;，& quot; & quot;，
& quot; & quot;，& quot; & quot;，& quot; gt & quot;）))
并且，对于每一列，我想找到值的范围（min 和 max？）并保存它们（例如在一个列表中）。
有什么简单的方法可以做到这一点？
谢谢！
英文:
I'm using the following matrix:
dput(data) =
structure(c(269.643848985434, 284.856715574861, 278.687093704939,242.00628682971, 258.754844814539, 257.241126745939, 250.868861973286,267.881099879742, 266.277047023177, 264.643696397543, 283.306375294924,278.137760534883, 251.230201125145, 264.389782398939, 260.087893307209,263.933225497603, 284.947050362825, 279.185155779123, 262.722251042724,284.903103709221, 279.329203143716, 256.589251384139, 274.861293360591,270.730307921767, 233.265785723925, 249.657887518406, 247.94396802783,264.665669724345, 284.124271348119, 278.701742589474, 0, 0, 0), dim = c(3L, 11L), dimnames = list(NULL, c("", "", "", "","", "", "", "", "", "", "gt")))
and, for each column, I'd like to find the range of values (min and max?) and save them (f.e. in a list).
What would be an easy way to do this?
Thank you!
答案1
得分: 3
我来帮你翻译代码部分：
让我引起你的注意，**matrixStats** 包。它不仅仅是语法糖，还是用C++实现的，因此非常快速。matrixStats::colRanges(m)# [,1] [,2]# 269.6438 284.8567# 242.0063 258.7548# 250.8689 267.8811# 264.6437 283.3064# 251.2302 264.3898# 263.9332 284.9471# 262.7223 284.9031# 256.5893 274.8613# 233.2658 249.6579# 264.6657 284.1243# gt 0.0000 0.0000
请注意，我只翻译了代码部分，没有包括其他内容。
英文:
Let me draw your attention to the matrixStats package. It's nut just syntactic sugar, it's also implemented in C++ and, thus, very fast.
matrixStats::colRanges(m)# [,1] [,2]# 269.6438 284.8567# 242.0063 258.7548# 250.8689 267.8811# 264.6437 283.3064# 251.2302 264.3898# 263.9332 284.9471# 262.7223 284.9031# 256.5893 274.8613# 233.2658 249.6579# 264.6657 284.1243# gt 0.0000 0.0000
答案2
得分: 2
你要找的函数是 range()：
range返回一个包含所有给定参数的最小值和最大值的向量。
使用 apply() 并设置 MARGIN = 2 来迭代每一列，应用 range() 函数。然后设置适当的行名称，例如 c("min", "max")。由于你想要一个列表，可以使用 asplit() 来将结果矩阵的列拆分为向量列表。
假设你的矩阵叫做 m：
apply(m, MARGIN = 2, range) |>`rownames<-`(c("min", "max")) |>asplit(MARGIN = 2)# [[1]]# min max# 269.6438 284.8567# [[2]]# min max# 242.0063 258.7548# [[3]]# min max# 250.8689 267.8811# [[4]]# min max# 264.6437 283.3064# [[5]]# min max# 251.2302 264.3898# [[6]]# min max# 263.9332 284.9471# [[7]]# min max# 262.7223 284.9031# [[8]]# min max# 256.5893 274.8613# [[9]]# min max# 233.2658 249.6579# [[10]]# min max# 264.6657 284.1243# $gt# min max# 0 0
英文:
The function you're looking for is range():
> range returns a vector containing the minimum and maximum of all the given arguments.
Use apply() with MARGIN = 2 to iterate over each column, applying the range() function. Then set appropriate row names, e.g. c("min", "max"). As you want a list, use asplit() to split the columns of the resulting matrix into a list of vectors.
Assuming your matrix is called m:
apply(m, MARGIN = 2, range) |>`rownames<-`(c("min", "max")) |>asplit(MARGIN = 2)# [[1]]# min max# 269.6438 284.8567# [[2]]# min max# 242.0063 258.7548# [[3]]# min max# 250.8689 267.8811# [[4]]# min max# 264.6437 283.3064# [[5]]# min max# 251.2302 264.3898# [[6]]# min max# 263.9332 284.9471# [[7]]# min max# 262.7223 284.9031# [[8]]# min max# 256.5893 274.8613# [[9]]# min max# 233.2658 249.6579# [[10]]# min max# 264.6657 284.1243# $gt# min max# 0 0
答案3
得分: 0
我们可以使用 tapply + col + range 来实现如下操作：
> tapply(data, col(data), range)$`1`[1] 269.6438 284.8567$`2`[1] 242.0063 258.7548$`3`[1] 250.8689 267.8811$`4`[1] 264.6437 283.3064$`5`[1] 251.2302 264.3898$`6`[1] 263.9332 284.9471$`7`[1] 262.7223 284.9031$`8`[1] 256.5893 274.8613$`9`[1] 233.2658 249.6579$`10`[1] 264.6657 284.1243$`11`[1] 0 0
英文:
We can use tapply + col + range like below
> tapply(data, col(data), range)$`1`[1] 269.6438 284.8567$`2`[1] 242.0063 258.7548$`3`[1] 250.8689 267.8811$`4`[1] 264.6437 283.3064$`5`[1] 251.2302 264.3898$`6`[1] 263.9332 284.9471$`7`[1] 262.7223 284.9031$`8`[1] 256.5893 274.8613$`9`[1] 233.2658 249.6579$`10`[1] 264.6657 284.1243$`11`[1] 0 0
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