计算每个矩阵列的min()和max()。

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英文:

Calculate min() and max() of each matrix column

问题

我使用以下矩阵:

dput(data) =

结构(c(269.643848985434,284.856715574861,278.687093704939,
242.00628682971,258.754844814539,257.241126745939,250.868861973286,
267.881099879742,266.277047023177,264.643696397543,283.306375294924,
278.137760534883,251.230201125145,264.389782398939,260.087893307209,
263.933225497603,284.947050362825,279.185155779123,262.722251042724,
284.903103709221,279.329203143716,256.589251384139,274.861293360591,
270.730307921767,233.265785723925,249.657887518406,247.94396802783,
264.665669724345,284.124271348119,278.701742589474,0,0,0
),dim = c(3L,11L),dimnames = list(NULL,c(& quot; & quot;,& quot; & quot;,& quot; & quot;,& quot; & quot;,
& quot; & quot;,& quot; & quot;,& quot; & quot;,& quot; & quot;,
& quot; & quot;,& quot; & quot;,& quot; gt & quot;)))

并且,对于每一列,我想找到值的范围(minmax?)并保存它们(例如在一个列表中)。

有什么简单的方法可以做到这一点?
谢谢!

英文:

I'm using the following matrix:

dput(data) =

structure(c(269.643848985434, 284.856715574861, 278.687093704939, 
242.00628682971, 258.754844814539, 257.241126745939, 250.868861973286, 
267.881099879742, 266.277047023177, 264.643696397543, 283.306375294924, 
278.137760534883, 251.230201125145, 264.389782398939, 260.087893307209, 
263.933225497603, 284.947050362825, 279.185155779123, 262.722251042724, 
284.903103709221, 279.329203143716, 256.589251384139, 274.861293360591, 
270.730307921767, 233.265785723925, 249.657887518406, 247.94396802783, 
264.665669724345, 284.124271348119, 278.701742589474, 0, 0, 0
), dim = c(3L, 11L), dimnames = list(NULL, c("", "", "", "", 
"", "", "", "", "", "", "gt")))

and, for each column, I'd like to find the range of values (min and max?) and save them (f.e. in a list).

What would be an easy way to do this?
Thank you!

答案1

得分: 3

我来帮你翻译代码部分:

让我引起你的注意,**matrixStats** 包。它不仅仅是语法糖,还是用C++实现的,因此非常快速。

matrixStats::colRanges(m)
#        [,1]     [,2]
#    269.6438 284.8567
#    242.0063 258.7548
#    250.8689 267.8811
#    264.6437 283.3064
#    251.2302 264.3898
#    263.9332 284.9471
#    262.7223 284.9031
#    256.5893 274.8613
#    233.2658 249.6579
#    264.6657 284.1243
# gt   0.0000   0.0000

请注意,我只翻译了代码部分,没有包括其他内容。

英文:

Let me draw your attention to the matrixStats package. It's nut just syntactic sugar, it's also implemented in C++ and, thus, very fast.

matrixStats::colRanges(m)
#        [,1]     [,2]
#    269.6438 284.8567
#    242.0063 258.7548
#    250.8689 267.8811
#    264.6437 283.3064
#    251.2302 264.3898
#    263.9332 284.9471
#    262.7223 284.9031
#    256.5893 274.8613
#    233.2658 249.6579
#    264.6657 284.1243
# gt   0.0000   0.0000

答案2

得分: 2

你要找的函数是 range()

range 返回一个包含所有给定参数的最小值和最大值的向量。

使用 apply() 并设置 MARGIN = 2 来迭代每一列,应用 range() 函数。然后设置适当的行名称,例如 c("min", "max")。由于你想要一个列表,可以使用 asplit() 来将结果矩阵的列拆分为向量列表。

假设你的矩阵叫做 m

apply(m, MARGIN = 2, range)  |>
    `rownames<-`(c("min", "max"))  |>
    asplit(MARGIN = 2)

# [[1]]
#      min      max 
# 269.6438 284.8567 

# [[2]]
#      min      max 
# 242.0063 258.7548 

# [[3]]
#      min      max 
# 250.8689 267.8811 

# [[4]]
#      min      max 
# 264.6437 283.3064 

# [[5]]
#      min      max 
# 251.2302 264.3898 

# [[6]]
#      min      max 
# 263.9332 284.9471 

# [[7]]
#      min      max 
# 262.7223 284.9031 

# [[8]]
#      min      max 
# 256.5893 274.8613 

# [[9]]
#      min      max 
# 233.2658 249.6579 

# [[10]]
#      min      max 
# 264.6657 284.1243 

# $gt
# min max 
#   0   0 
英文:

The function you're looking for is range():

> range returns a vector containing the minimum and maximum of all the given arguments.

Use apply() with MARGIN = 2 to iterate over each column, applying the range() function. Then set appropriate row names, e.g. c("min", "max"). As you want a list, use asplit() to split the columns of the resulting matrix into a list of vectors.

Assuming your matrix is called m:

apply(m, MARGIN = 2, range)  |>
    `rownames<-`(c("min", "max"))  |>
    asplit(MARGIN = 2)

# [[1]]
#      min      max 
# 269.6438 284.8567 

# [[2]]
#      min      max 
# 242.0063 258.7548 

# [[3]]
#      min      max 
# 250.8689 267.8811 

# [[4]]
#      min      max 
# 264.6437 283.3064 

# [[5]]
#      min      max 
# 251.2302 264.3898 

# [[6]]
#      min      max 
# 263.9332 284.9471 

# [[7]]
#      min      max 
# 262.7223 284.9031 

# [[8]]
#      min      max 
# 256.5893 274.8613 

# [[9]]
#      min      max 
# 233.2658 249.6579 

# [[10]]
#      min      max 
# 264.6657 284.1243 

# $gt
# min max 
#   0   0 

答案3

得分: 0

我们可以使用 tapply + col + range 来实现如下操作:

> tapply(data, col(data), range)
$`1`
[1] 269.6438 284.8567

$`2`
[1] 242.0063 258.7548

$`3`
[1] 250.8689 267.8811

$`4`
[1] 264.6437 283.3064

$`5`
[1] 251.2302 264.3898

$`6`
[1] 263.9332 284.9471

$`7`
[1] 262.7223 284.9031

$`8`
[1] 256.5893 274.8613

$`9`
[1] 233.2658 249.6579

$`10`
[1] 264.6657 284.1243

$`11`
[1] 0 0
英文:

We can use tapply + col + range like below

> tapply(data, col(data), range)
$`1`
[1] 269.6438 284.8567

$`2`
[1] 242.0063 258.7548

$`3`
[1] 250.8689 267.8811

$`4`
[1] 264.6437 283.3064

$`5`
[1] 251.2302 264.3898

$`6`
[1] 263.9332 284.9471

$`7`
[1] 262.7223 284.9031

$`8`
[1] 256.5893 274.8613

$`9`
[1] 233.2658 249.6579

$`10`
[1] 264.6657 284.1243

$`11`
[1] 0 0

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  • 本文由 发表于 2023年7月5日 00:43:47
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