英文:
pmap_dbl is not working with lambda function
问题
我正在尝试使用pmap_dbl按行找到列的总和。如果我使用sum而不是\(x) sum(x)，它可以正常工作。有任何想法吗？
pacman::p_load(tidyverse)country_df <- tibble(population = c(328, 38, 30, 56, 1393, 126, 57),population2 = c(133, 12, 99, 83, 1033, 101, 33),population3 = c(89, 39, 33, 56, 193, 126, 58),pop = 45)# 正常工作country_df |> mutate(sum = pmap_dbl(pick(1:3),sum))#> # A tibble: 7 × 5#> population population2 population3 pop sum#> <dbl> <dbl> <dbl> <dbl> <dbl>#> 1 328 133 89 45 550#> 2 38 12 39 45 89#> 3 30 99 33 45 162#> 4 56 83 56 45 195#> 5 1393 1033 193 45 2619#> 6 126 101 126 45 353#> 7 57 33 58 45 148# 不正常工作country_df |> mutate(sum = pmap_dbl(pick(1:3), \(x) sum(x)))#> Error in `mutate()`:#> ℹ In argument: `sum = pmap_dbl(pick(1:3), function(x) sum(x))`.#> Caused by error in `pmap_dbl()`:#> ℹ In index: 1.#> Caused by error in `.f()`:#> ! unused arguments (population = .l[[1]][[i]], population2 = .l[[2]][[i]], population3 = .l[[3]][[i]])#> Backtrace:#> ▆#> 1. ├─dplyr::mutate(country_df, sum = pmap_dbl(pick(1:3), function(x) sum(x)))#> 2. ├─dplyr:::mutate.data.frame(...)#> 3. │ └─dplyr:::mutate_cols(.data, dplyr_quosures(...), by)#> 4. │ ├─base::withCallingHandlers(...)#> 5. │ └─dplyr:::mutate_col(dots[[i]], data, mask, new_columns)#> 6. │ └─mask$eval_all_mutate(quo)#> 7. │ └─dplyr (local) eval()#> 8. ├─purrr::pmap_dbl(...)#> 9. │ └─purrr:::pmap_("double", .l, .f, ..., .progress = .progress)#> 10. │ ├─purrr:::with_indexed_errors(...)#> 11. │ │ └─base::withCallingHandlers(...)#> 12. │ └─purrr:::call_with_cleanup(...)#> 13. └─base::.handleSimpleError(...)#> 14. └─purrr (local) h(simpleError(msg, call))#> 15. └─cli::cli_abort(...)#> 16. └─rlang::abort(...)
创建于2023-07-03，使用reprex v2.0.2
英文:
I am trying to find the sum of columns rowwise using pmap_dbl. If I use sum instead of \(x) sum(x) it is working. Any ideas?
pacman::p_load(tidyverse)country_df <- tibble(population = c(328, 38, 30, 56, 1393, 126, 57),population2 = c(133, 12, 99, 83, 1033, 101, 33),population3 = c(89, 39, 33, 56, 193, 126, 58),pop = 45)# workingcountry_df |> mutate(sum = pmap_dbl(pick(1:3),sum))#> # A tibble: 7 × 5#> population population2 population3 pop sum#> <dbl> <dbl> <dbl> <dbl> <dbl>#> 1 328 133 89 45 550#> 2 38 12 39 45 89#> 3 30 99 33 45 162#> 4 56 83 56 45 195#> 5 1393 1033 193 45 2619#> 6 126 101 126 45 353#> 7 57 33 58 45 148# not workingcountry_df |> mutate(sum = pmap_dbl(pick(1:3), \(x) sum(x)))#> Error in `mutate()`:#> ℹ In argument: `sum = pmap_dbl(pick(1:3), function(x) sum(x))`.#> Caused by error in `pmap_dbl()`:#> ℹ In index: 1.#> Caused by error in `.f()`:#> ! unused arguments (population = .l[[1]][[i]], population2 = .l[[2]][[i]], population3 = .l[[3]][[i]])#> Backtrace:#> ▆#> 1. ├─dplyr::mutate(country_df, sum = pmap_dbl(pick(1:3), function(x) sum(x)))#> 2. ├─dplyr:::mutate.data.frame(...)#> 3. │ └─dplyr:::mutate_cols(.data, dplyr_quosures(...), by)#> 4. │ ├─base::withCallingHandlers(...)#> 5. │ └─dplyr:::mutate_col(dots[[i]], data, mask, new_columns)#> 6. │ └─mask$eval_all_mutate(quo)#> 7. │ └─dplyr (local) eval()#> 8. ├─purrr::pmap_dbl(...)#> 9. │ └─purrr:::pmap_("double", .l, .f, ..., .progress = .progress)#> 10. │ ├─purrr:::with_indexed_errors(...)#> 11. │ │ └─base::withCallingHandlers(...)#> 12. │ └─purrr:::call_with_cleanup(...)#> 13. └─base::.handleSimpleError(...)#> 14. └─purrr (local) h(simpleError(msg, call))#> 15. └─cli::cli_abort(...)#> 16. └─rlang::abort(...)
<sup>Created on 2023-07-03 with reprex v2.0.2</sup>
答案1
得分: 3
pmap与map或map2函数有些不同，其中您可以传递的值数量是固定的。在pmap函数中，您可以传递任意数量的参数，这些参数可以使用三个点（...）来捕获。
library(dplyr)library(purrr)country_df |> mutate(sum = pmap_dbl(pick(1:3), \(...) sum(...)))# population population2 population3 pop sum# <dbl> <dbl> <dbl> <dbl> <dbl>#1 328 133 89 45 550#2 38 12 39 45 89#3 30 99 33 45 162#4 56 83 56 45 195#5 1393 1033 193 45 2619#6 126 101 126 45 353#7 57 33 58 45 148
英文:
pmap is a bit different than map or map2 functions where the number of values that you can pass is fixed. In pmap functions you can pass any number of arguments which can be captured with three dots. (...).
library(dplyr)library(purrr)country_df |> mutate(sum = pmap_dbl(pick(1:3), \(...) sum(...)))# population population2 population3 pop sum# <dbl> <dbl> <dbl> <dbl> <dbl>#1 328 133 89 45 550#2 38 12 39 45 89#3 30 99 33 45 162#4 56 83 56 45 195#5 1393 1033 193 45 2619#6 126 101 126 45 353#7 57 33 58 45 148
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