英文:
Convert a String into a List in Kotlin
问题
在Kotlin中，我从服务器收到这个字符串形式的地理坐标列表：
[[45.02498, 7.55163], [45.02527, 7.55167], [45.02556, 7.55172],[45.02564, 7.55173], [45.02582, 7.55175], [45.02582, 7.55188],[45.02585, 7.55202], [45.02593, 7.55213], [45.026, 7.55218]]
我该如何从这个字符串创建一个Pair的列表？我看到可以使用正则表达式，但我并没有真正理解如何使用它，尤其是处理起始和结束的方括号。
英文:
In kotlin, I receive from a server this list of geocoordinates as a string:
> [[45.02498, 7.55163], [45.02527, 7.55167], [45.02556, 7.55172],
> [45.02564, 7.55173], [45.02582, 7.55175], [45.02582, 7.55188],
> [45.02585, 7.55202], [45.02593, 7.55213], [45.026, 7.55218]]
How can I create a List of Pairs starting from this string? I've seen that is possible to use Regex, but I've not really understood how to use it, expecially having to deal with a starting and ending square parenthesis.
答案1
得分: 1
这个解决方案实际上非常简单，这是一个代码示例。
字符串已转换为一个JSONArray，通过一个 for 循环可以访问所有元素，提取所需的数据。
val jsonArray = JSONArray(receivedText)for (i in 0 until jsonArray.length()) {val pairArray = jsonArray.getJSONArray(i)val latitude = pairArray.getDouble(0)val longitude = pairArray.getDouble(1)Log.d("description","Pair $i - Latitude: $latitude, Longitude: $longitude")}
英文:
The solution actually was very simple, and this is an instance of code.
The string has been transformed into a JSONArray and through a for loop it's possible to have access to all the elements, extracting the desired data.
val jsonArray = JSONArray(receivedText)for (i in 0 until jsonArray.length()) {val pairArray = jsonArray.getJSONArray(i)val latitude = pairArray.getDouble(0)val longitude = pairArray.getDouble(1)Log.d("description","Pair $i - Latitude: $latitude, Longitude: $longitude")
答案2
得分: 0
尝试这个：
val jsonString = "[[45.02498, 7.55163], [45.02527, 7.55167], [45.02556, 7.55172], [45.02564, 7.55173], [45.02582, 7.55175], [45.02582, 7.55188], [45.02585, 7.55202], [45.02593, 7.55213], [45.026, 7.55218]]"val withoutBrackets = jsonString.removeSurrounding("[", "]")val pairs = withoutBrackets.split("], [")val pairList: List<Pair<Double, Double>> = pairs.map {val coords = it.removeSurrounding("[", "]").split(", ")Pair(coords[0].toDouble(), coords[1].toDouble())}println(pairList)
英文:
Try this:
val jsonString = "[[45.02498, 7.55163], [45.02527, 7.55167], [45.02556, 7.55172], [45.02564, 7.55173], [45.02582, 7.55175], [45.02582, 7.55188], [45.02585, 7.55202], [45.02593, 7.55213], [45.026, 7.55218]]"val withoutBrackets = jsonString.removeSurrounding("[", "]")val pairs = withoutBrackets.split("], [")val pairList: List<Pair<Double, Double>> = pairs.map {val coords = it.removeSurrounding("[", "]").split(", ")Pair(coords[0].toDouble(), coords[1].toDouble())}println(pairList)
答案3
得分: 0
这个答案可以是一个解决方案！fun parseString(str: String): MutableList<Pair<Double, Double>> {val pairs = mutableListOf<Pair<Double, Double>>()val elements = str.removeSurrounding("[[", "]]").replace(" ", "").split("],[")elements.forEach { element ->val (firstElement, secondElement) = element.split(",")val pair = Pair(firstElement.toDouble(), secondElement.toDouble())pairs.add(pair)}return pairs}
英文:
This answer can be a solution!
fun parseString(str: String): MutableList<Pair<Double, Double>> {val pairs = mutableListOf<Pair<Double, Double>>()val elements = str.removeSurrounding("[[", "]]").replace(" ", "").split("],[")elements.forEach { element ->val (firstElement, secondElement) = element.split(",")val pair = Pair(firstElement.toDouble(), secondElement.toDouble())pairs.add(pair)}return pairs}
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