英文:
Go Build remove information
问题
我已经可以使用Go Build命令来去除项目的当前目录信息，或者去除GOPATH信息，像下面这样，现在我只能分别删除其中一个：
go build -gcflags "all=-trimpath=${GOPATH}" -asmflags "all=-trimpath=${GOPATH}"
但是我不知道如何同时删除它们，我不知道如何组合它们。
在Windows上，我尝试了这个：
go build -gcflags "all=-trimpath=%CD%" -asmflags "all=-trimpath=%CD%" -gcflags "all=-trimpath=%GOPATH%" -asmflags "all=-trimpath=%GOPATH%"
但是它没有起作用。
最终结果
@ZekeLu，答案是正确的。
我想解释一下发生了什么，我本来期望删除的是GOROOT信息，但是我写成了GOPATH，所以我以为@ZekeLu的第二个答案是错误的，现在我已经修改并测试过了，没有问题，两个答案都是正确的。
英文:
I can already use Go Build to remove the current directory information of the project, or I can remove Gopath information, like the following, I can only delete one of them separately now
go build -gcflags "all=-trimpath=${GOPATH}" -asmflags "all=-trimpath=${GOPATH}"
But I don’t know how to remove them at the same time, I don’t know how to combine it
on windows, i try this
go build -gcflags "all=-trimpath=%CD%" -asmflags "all=-trimpath=%CD%" -gcflags "all=-trimpath=%GOPATH%" -asmflags "all=-trimpath=%GOPATH%"
It does not work
Final Results
@ZekeLu,the answer is right.
I want to explain what happened, I expected to remove GOROOT information, but I wrote GOPATH, so I thought @ZekeLu's second answer was wrong, now I have modified and tested, there is no problem, two answers all right
答案1
得分: 0
尝试使用以下命令：
go build -trimpath
这是关于-trimpath标志的文档，适用于Go命令：
-trimpath
从生成的可执行文件中删除所有文件系统路径。
记录的文件名将以模块路径@版本（使用模块时）或纯导入路径（使用标准库或GOPATH时）开头，而不是绝对文件系统路径。
如果你只想删除一些前缀，可以像这样操作：
go build -gcflags "all=-trimpath=%CD%;%GOPATH%" -asmflags "all=-trimpath=%CD%;%GOPATH%"
编译命令和汇编命令都调用了objabi.ApplyRewrites来修剪路径。根据objabi.ApplyRewrites的实现，rewrites参数是一个以分号分隔的重写列表。
// ApplyRewrites根据重写参数对给定目录中的文件进行重写，并返回文件名。
//
// 重写参数是一个以分号分隔的重写列表。
// 每个重写的格式为“prefix”或“prefix=>replace”，
// 其中prefix必须匹配路径元素的前导序列，
// 并且可以完全删除或替换为替换字符串。
func ApplyRewrites(file, rewrites string) (string, bool) {
start := 0
for i := 0; i <= len(rewrites); i++ {
if i == len(rewrites) || rewrites[i] == ';' {
if new, ok := applyRewrite(file, rewrites[start:i]); ok {
return new, true
}
start = i + 1
}
}
return file, false
}
英文:
Try this command:
go build -trimpath
Here is the doc for the -trimpath flag for the Go command:
> -trimpath
>
> remove all file system paths from the resulting executable.
Instead of absolute file system paths, the recorded file names
will begin either a module path@version (when using modules),
or a plain import path (when using the standard library, or GOPATH).
If you only want to remove some of the prefixes, you can do it like this:
go build -gcflags "all=-trimpath=%CD%;%GOPATH%" -asmflags "all=-trimpath=%CD%;%GOPATH%"
Both the Compile command and the Asm command calls objabi.ApplyRewrites to trim paths. According to the implementation of objabi.ApplyRewrites, The rewrites argument is a ;-separated list of rewrites.
// ApplyRewrites returns the filename for file in the given directory,
// as rewritten by the rewrites argument.
//
// The rewrites argument is a ;-separated list of rewrites.
// Each rewrite is of the form "prefix" or "prefix=>replace",
// where prefix must match a leading sequence of path elements
// and is either removed entirely or replaced by the replacement.
func ApplyRewrites(file, rewrites string) (string, bool) {
start := 0
for i := 0; i <= len(rewrites); i++ {
if i == len(rewrites) || rewrites[i] == ';' {
if new, ok := applyRewrite(file, rewrites[start:i]); ok {
return new, true
}
start = i + 1
}
}
return file, false
}
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