Is it possible to return a member variable of a class specified by a template function?

I am trying to generalize a function for a game engine I am writing to simplify the shader loading process.

Anyway, the difficulty arises in my attempts to templating the function. I attempted to adapt the solution found in this stack thread, and resulted in various versions of the following code without any ideal solutions:

template<typename T, typename U, U T::* x>
U testFunc(T& t)
{ 
    // Simplification of the extremely generalized function;
    // I want to return/utilize member variable x of input t
    return x;
}
struct testS1 { int a = 100; };
struct testS2 { bool b = true; };
testS1 tS1;
testS2 tS2;
// would ideally return 100
int c = testFunc<testS1, int, &testS1::a>(tS1);
// would ideally return true 
bool d = testFunc<testS2, bool, &testS2::b>(tS2);

Running the program gives the following error:

Severity: Error
Line: 46
Code: C2440
Description: 'return': cannot convert from 'int testS1::* ' to 'U'

I understand that the returned value x is not the same type as U because int testS1::* is not the same type as int.

However, I do not understand what syntax I would use to return the member variable x of type U from the struct T.

The real structs behind the placeholders testS1 and testS2 are very different from each other, so I would like to avoid using a base class/struct if at all possible.

template<class T, class U, U T::*x>
U testFunc(T& t)
{
    return t.*x;
}

You simply need to dereference x to get a U.

The other answer has already provided the syntax for accessing the pointer to the member data. In [tag:C++20] using abbreviated function template, you could do it, less verbosely the same

template<auto  x>
constexpr auto testFunc(auto const& t)
{
    return t.*x;
}

Now you call with less explicate template arguments

int c = testFunc<&testS1::a>(tS1);
bool d = testFunc<&testS2::b>(tS2);
// ...

See a demo in godbolt.org