英文:
Graph parabola in matplotlib with vertex and 2 'end' points known
问题
尝试创建一个抛物线矢量，其中顶点和抛物线上的另外两个点已知。
示例...
- 范围从0到10
- 顶点 = [5,2]
- 坐标1 = [1,1]
- 坐标2 = [10,1]
任何帮助/建议都将不胜感激。
谢谢
英文:
Trying to create a parabolic vector of values where the Vertex and two other points along the parabola are known.
Example...
- Range from 0 to 10
- Vertex = [5,2]
- Coordinate 1 = [1,1]
- Coordinate 2= [10,1]
Any help/advice is greatly appreciated.
Thanks
答案1
得分: 1
import matplotlib.pyplot as pltimport numpy as np# 点x = [1, 5, 10]y = [1, 2, 1]# 使用 polyfit 来拟合通过这些点的二次多项式poly_coeffs = np.polyfit(x, y, 2)# 评估多项式找到的值# 评估点的向量 xxxmin = 0xmax = 10xx = np.linspace(xmin, xmax, 100)yy = np.polyval(poly_coeffs, xx) # y 坐标# 画图plt.figure()plt.plot(x, y, 'or')plt.plot(xx, yy)plt.grid()plt.ylim([-3, 4])plt.xlim([-0.5, 12])
这会绘制出下面的图像：
英文:
I would use numpy to adjust a parabola passing by the points with polyfit, and then polyval to evaluate the polynomial found:
import matplotlib.pyplot as pltimport numpy as np#pointsx = [1, 5, 10]y = [1, 2, 1]poly_coeffs = np.polyfit(x,y,2) #fit a polynomial with degree=2#evaluation points vector xxxmin = 0xmax = 10xx = np.linspace(xmin, xmax, 100)yy = np.polyval(poly_coeffs, xx) #y coords#plotingplt.figure()plt.plot(x,y,'or')plt.plot(xx,yy)plt.grid()plt.ylim([-3,4])plt.xlim([-0.5,12])
This would draw the next image:
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