英文:
I have a code which is correct in a 3 years back flutter but not in the current flutter version
问题
以下是您提供的代码片段的翻译:
这是一个名为UniqueId的类,它是一个值对象。用于检查相等性等等。
class UniqueId extends ValueObject<String> {
@override
final Either<ValueFailure<String>, String> value;
factory UniqueId() {
return UniqueId._(
Right(const Uuid().v1())
);
}
factory UniqueId.fromUniqueString(String uniqueId) {
return UniqueId._(Right(uniqueId));
}
const UniqueId._(
this.value,
);
}
然后我使用了freezed。
@freezed
abstract class User1 with _$User1{
const factory User1(
{required UniqueId id,}
) = _User1;
}
现在我提供我遇到问题的部分。
@LazySingleton(as: IauthFailure)
class FirebaseAuthFailure implements IauthFailure {
final FirebaseAuth firebaseAuth;
final GoogleSignIn googleSignIn;
FirebaseAuthFailure(this.firebaseAuth, this.googleSignIn);
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser().then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
我遇到的错误如下:
错误1:无法无条件调用该函数,因为它可能为null。
我使用的解决方案:
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser!().then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
错误2:该表达式不会评估为函数,因此无法调用。
我使用的解决方案:
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser!.then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
错误3:该方法'then'对于类型'User'未定义。
我无法找到解决方案。
'toDomain()'的定义如下:
extension FirebaseUserDomainX on User {
User1 toDomain() {
return User1(id: UniqueId.fromUniqueString(uid));
}
}
实际上,当我将鼠标悬停在上面并点击跳转到定义时,它显示没有定义。
英文:
This is a class UniqueId which is a valueobject. This is for checking equality and all that
class UniqueId extends ValueObject<String> {
@override
final Either<ValueFailure<String>, String> value;
factory UniqueId() {
return UniqueId._(
Right(const Uuid().v1())
);
}
factory UniqueId.fromUniqueString(String uniqueId) {
return UniqueId._(Right(uniqueId));
}
const UniqueId._(
this.value,
);
}
Then I have used freezed.
@freezed
abstract class User1 with _$User1{
const factory User1(
{required UniqueId id,}
) = _User1;
}
Now I am giving the part I am having problem with
@LazySingleton(as: IauthFailure)
class FirebaseAuthFailure implements IauthFailure {
final FirebaseAuth firebaseAuth;
final GoogleSignIn googleSignIn;
FirebaseAuthFailure(this.firebaseAuth, this.googleSignIn);
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser().then((firebaseUser) =>
optionOf(firebaseUser?.toDomain()));
The error I am getting is given below:
error1: The function can't be unconditionally invoked because it can be 'null'.
solution I used:
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser!().then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
error2:the expression doesn't evaluate to a function, so it can't be invoked.
solution I used:
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser!.then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
error3:The method 'then' isn't defined for the type 'User'.
Try correcting the name to the name of an existing method, or defining a method named 'then'.
solution I used: Cannot find a solution
The definition of toDomain()
is :
extension FirebaseUserDomainX on User {
User1 toDomain() {
return User1(id: UniqueId.fromUniqueString(uid));
}
}
Actually I am not getting this toDomain
when I am hovering over it and click go to definition its saying no defintion.
答案1
得分: 0
If i understood it correctly (your question is not very clear), you should update your code accordingly to deprecated methods.
currentUser is not a method anymore, but it is a getter.
also I'm assuming _firebaseAuth
is an instance of FirebaseAuth
@override
Future<Option<User>> getSignedInUser() async {
User? firebaseUser = _firebaseAuth.currentUser;
return optionOf(firebaseUser?.toDomain());
}
It would be very valuable if you posted the error that you're getting when using optionOf
.
英文:
If i understood it correctly (your question is not very clear), you should update your code accordingly to deprecated methods.
currentUser is not a method anymore, but it is a getter.
also I'm assuming _firebaseAuth
is an instance of FirebaseAuth
@override
Future<Option<User>> getSignedInUser() async {
User? firebaseUser = _firebaseAuth.currentUser;
return optionOf(firebaseUser?.toDomain());
}
It would be very valuable if you posted the error that you're getting when using optionOf
答案2
得分: 0
I have found the solution of this error this code is deprecated. that's why is not working properly.
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser!.then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
see this solution and try it. I have made a simple solution for the deprecated code it's run properly.
@override
Future<Option<User>> getSignedInUser() async {
final firebaseUser = _firebaseAuth.currentUser;
if (firebaseUser != null) {
return optionOf(firebaseUser.toDomain());
} else {
return none();
}
}
英文:
I have found the solution of this error this code is deprecated. that's why is not working properly.
@override
Future<Option<User1>> getSignedInUser() =>
firebaseAuth.currentUser!.then((firebaseUser) => optionOf(firebaseUser?.toDomain()));
see this solution and try it. I have made a simple solution for the deprecated code it's run properly.
@override
Future<Option<User>> getSignedInUser() async {
final firebaseUser = _firebaseAuth.currentUser;
if (firebaseUser != null) {
return optionOf(firebaseUser.toDomain());
} else {
return none();
}
}
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