英文:
java regex with curly braces
问题
我在解决这个特定问题时遇到了困难
输入: [{"acks":"6"},{"acks":"7"},{"acks":"8"}]
正则表达式: [{]*["acks:"]
当前输出: [6},7},8}]
期望输出: [6,7,8]
我遇到了结束花括号的问题。
提前感谢您的帮助！
英文:
I am having hard time solving this particular problem
input: [{"acks":"6"},{"acks":"7"},{"acks":"8"}]
regex: [\{]*["acks:"]
current output: [6},7},8}]
desired output: [6,7,8]
I am facing problem with the ending curly braces.
Thank you for helping me in advance!!
答案1
得分: 1
你可以尝试这个正则表达式 (?:\"[\\w]+\":\")(\\d+)
import java.util.regex.*;
import java.util.*;
import java.util.function.Supplier;
class HelloWorld {
public static void main(String[] args) {
Pattern p = Pattern.compile("(?:\"[\\w]+\":\")(\\d+)");
Matcher m = p.matcher("[{\"acks\":\"6\"},{\"acks\":\"7\"},{\"acks\":\"8\"}]\t");
List<String> llist = new LinkedList<String>();
while (m.find()) {
llist.add(m.group(1));
}
if(llist.size() == 0) {
System.out.println("No match found.");
} else {
System.out.println("Output : " + llist.toString());
}
}
}
英文:
You can try this regexp (?:\"[\\w]+\":\")(\\d+)
import java.util.regex.*;
import java.util.*;
import java.util.function.Supplier;
class HelloWorld {
public static void main(String[] args) {
Pattern p = Pattern.compile("(?:\"[\\w]+\":\")(\\d+)");
Matcher m = p.matcher("[{\"acks\":\"6\"},{\"acks\":\"7\"},{\"acks\":\"8\"}]\t");
List<String> llist = new LinkedList<String>();
while (m.find()) {
llist.add(m.group(1));
}
if(llist.size() == 0) {
System.out.println("No match found.");
} else {
System.out.println("Output : " + llist.toString());
}
}
}
答案2
得分: 0
以下是翻译好的部分：
如果你只想要去掉 [,],, 和数字，你可以使用以下正则表达式将其他所有内容替换为空字符串：[^\d,[\]]+
如果你只需要从具有单一字段 "acks" 的对象中提取数字，你可以使用 $1 替换\{"acks":"(\d+)"\}。
演示在这里。
英文:
It is unclear precisely what you are trying to do.
If all you want is to leave out [,],, and digits, you can replace everything else with empty string using the following regex: [^\d,[\]]+
And if you only need to extract digits from objects with single field "acks", you could replace \{"acks":"(\d+)"\} with $1.
Demo here.
答案3
得分: 0
只需检查\"acks\"、:字符以及起始和结束的"字符。
检查{ 似乎不必要。
\"acks\":\"(.+?)\"
String string = "{\"acks\":\"6\"},{\"acks\":\"7\"},{\"acks\":\"8\"}";
Pattern pattern = Pattern.compile("\\\"acks\\\":\\\"(.+?)\\\"");
Matcher matcher = pattern.matcher(string);
List<String> list = new ArrayList<>();
while (matcher.find()) list.add(matcher.group(1));
输出
[6, 7, 8]
英文:
Just check for \"acks\", the : character, and the starting and ending " characters.
The check for { doesn't seem necessary.
\"acks\":\"(.+?)\"
String string = "{\"acks\":\"6\"},{\"acks\":\"7\"},{\"acks\":\"8\"}";
Pattern pattern = Pattern.compile("\\\"acks\\\":\\\"(.+?)\\\"");
Matcher matcher = pattern.matcher(string);
List<String> list = new ArrayList<>();
while (matcher.find()) list.add(matcher.group(1));
Output
[6, 7, 8]
答案4
得分: -1
这应该适用于描述的情况：
System.out.println("[{\"acks\":\"6\"},{\"acks\":\"17\"},{\"acks\":\"888\"}]".replaceAll("(\\{\"acks\":)*(\"})*", ""));
结果：[6,17,888]
我可以看到有一些评论说，与“acks”键不同，可能是任何符号，因此我建议使用以下正则表达式：(\{.*?:\"\d*\"\},)* 参见 https://regex101.com/r/kfAYsQ/1
System.out.println("[{\"key1\":\"6\"},{\"key2\":\"17\"},{\"key3\":\"888\"}]".replaceAll("(\\{.*?:\"\d*\"\},)*", ""));
输入：[{"key1":"6"},{"key2":"17"},{"key3":"888"}]
结果：[6,17,888]
英文:
This should work for the described case:
System.out.println("[{\"acks\":\"6\"},{\"acks\":\"17\"},{\"acks\":\"888\"}]".replaceAll("(\\{\"acks\":\")*(\"})*", ""));
Result: [6,17,888]
I can see that there are some comments that instead of "acks" key might be any symbols, hence I would suggest to use next regexp (\{.*?:\")*(\"})* see https://regex101.com/r/kfAYsQ/1
System.out.println("[{\"key1\":\"6\"},{\"key2\":\"17\"},{\"key3\":\"888\"}]".replaceAll("(\\{.*?:\")*(\"})*", ""));
input: [{\"key1\":\"6\"},{\"key2\":\"17\"},{\"key3\":\"888\"}]
result: [6,17,888]
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