英文:
Swift protocol conformance with async overload
问题
为什么这段代码能够成功编译和运行？（Swift 5.8）
protocol AsyncOverloaded {
func load()
func load() async throws
}
class MyClass: AsyncOverloaded {
func load() {
print("load called")
}
}
let myClass = MyClass()
myClass.load()
// 输出 "load called"
据我理解，MyClass 实际上并没有遵循协议 AsyncOverloaded。
英文:
Why does this successfully compile and run? (Swift 5.8)
protocol AsyncOverloaded {
func load()
func load() async throws
}
class MyClass: AsyncOverloaded {
func load() {
print("load called")
}
}
let myClass = MyClass()
myClass.load()
// prints "load called"
To my understanding MyClass does actually not conform to protocol AsyncOverloaded.
Thanks in advance.
答案1
得分: 3
MyClass 中的 load() 函数同时满足协议要求。非抛出异常的函数可以满足需要抛出异常的函数的要求，因为它就像一个永远不会真正抛出异常的抛出异常函数一样。同样，同步函数可以满足 async 的要求。
英文:
The function load() in MyClass satisfies both protocol requirements.
A non throwing function satisfies a requirement for a throwing function since it's just like a throwing function that never actually throws. Similarly a synchronous function can satisfy an async requirement.
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