英文:
What method is called when using dot notation in MyClass.my_attribute?
问题
我想要在使用点表示法获取属性时打印"获取 x 属性"。
例如：
class MyClass:my_attribute = "abc"print(MyClass.my_attribute)
我期望它的输出如下：
>>> 获取 my_attribute 属性>>> abc
我没有实例化该类。
我尝试在MyClass.__getattr__()和MyClass.__getattribute__()中添加打印语句，但这两者都不会显示任何内容。
我尝试了以下方法：
class MyClass:def __getattr__(self, key):print("运行 __getattr__")return super().__getattr__(key)def __getattribute__(self, __name: str) -> Any:print("运行 __getattribute__")return super().__getattribute__(__name)my_attribute = "abc"
英文:
I want to print "getting x attr" whenever I use the dot notation to get an attribute.
For example
class MyClass:my_attribute = "abc"print(MyClass.my_attribute)
I'd expect it to output like this:
>>> getting my_attribute attr>>> abc
I'm not instantiating the class.
I tried to add a print statement to MyClass.__getattr__() and MyClass.__getattribute__() but none of these will display anything.
I tried the following:
class MyClass:def __getattr__(self, key):print("running __getattr__")return super().__getattr__(key)def __getattribute__(self, __name: str) -> Any:print("running __getattribute__")return super().__getattribute__(__name)my_attribute = "abc"
答案1
得分: 4
MyClass（类对象本身）本身就是一个对象。您想在类MyClass的实例上定义自己的__getattribute__方法。要做到这一点，可以使用元类：
class MyMeta(type):def __getattribute__(self, item):print(f"获取 {item}")return super().__getattribute__(item)class MyClass(metaclass=MyMeta):my_class_attribute = "abc"
然后
print(type(MyClass))print(MyClass.my_class_attribute)
输出
<class '__main__.MyMeta'>获取 my_class_attributeabc
英文:
MyClass (the class object) is itself an object. You want to define your custom __getattribute__ method on the class that MyClass is an instance of. To do that, use a metaclass:
class MyMeta(type):def __getattribute__(self, item):print(f"getting {item}")return super().__getattribute__(item)class MyClass(metaclass=MyMeta):my_class_attribute = "abc"
then
print(type(MyClass))print(MyClass.my_class_attribute)
outputs
<class '__main__.MyMeta'>getting my_class_attributeabc
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