英文:
'undefined columns selected'-error in R when expanding rows based on column values (not missing comma, not faulty heading)
问题
我有一个名为'google_removal'的数据集，包含5列和14,468行。我试图根据指定每行观测频率的值来扩展行数。
然而，我一直收到'未定义的列被选择'的错误消息。据我所见，这不是因为忘记添加逗号的问题，我已检查了相关列是否有我使用的特定标题。
频率在'总计'列中指定，是数值型的，其他变量是字符型的。我是一个完全初学者，如果问题结构不好，请原谅。
数据看起来像这样。如果需要更多信息，我可以提供。
'期末日期' '国家' '代码' '产品' '原因' '总计' '年份'2011-06-30 阿根廷 AR 博客 诽谤 4 20112011-06-30 阿根廷 AR 博客 隐私 1 20112011-06-30 阿根廷 AR GoogleAd 诽谤 1 20112011-06-30 阿根廷 AR WebSearch 诽谤 6 2011
我尝试实现以下目标:
'期末日期' '国家' '代码' '产品' '原因' '年份'2011-06-30 阿根廷 AR 博客 诽谤 20112011-06-30 阿根廷 AR 博客 诽谤 20112011-06-30 阿根廷 AR 博客 诽谤 20112011-06-30 阿根廷 AR 博客 诽谤 20112011-06-30 阿根廷 AR 博客 隐私 20112011-06-30 阿根廷 AR GoogleAd 诽谤 20112011-06-30 阿根廷 AR WebSearch 诽谤 20112011-06-30 阿根廷 AR WebSearch 诽谤 20112011-06-30 阿根廷 AR WebSearch 诽谤 20112011-06-30 阿根廷 AR WebSearch 诽谤 20112011-06-30 阿根廷 AR WebSearch 诽谤 20112011-06-30 阿根廷 AR WebSearch 诽谤 2011
我尝试了以下操作（'total'是我想要用来扩展行数的列的标题），并且是从一个关于扩展行的问题的答案中进行了适应。
google_removal_expanded <- google_removal[seq_len(nrow(google_removal), google_removal$total), 1:13000]google_removal_expanded <- google_removal[rep(row.names(google_removal), google_removal$total), 1:13000]
我期望其中一个能返回扩展后的数据框，但实际上我收到了变化的错误消息：
"Error in
[.data.frame(google_removal, rep(row.names("total"),
google_removal$total), : undefined columns selected" 对于两者都是如此。
感谢任何帮助。我尝试解决这个问题时，是根据以下答案进行的
https://stackoverflow.com/questions/2894775/repeat-each-row-of-data-frame-the-number-of-times-specified-in-a-column
以下是一些数据以供尝试：
dput(head(google_removal))
" 2011-06-30 "，" 2011-06-30 "，" 2011-06-30 "，" 2011-06-30 "），国家= c（"阿根廷"，"阿根廷"，"阿根廷"，"阿根廷"，"阿根廷"，"阿根廷"），代码= c（" AR "，" AR "，" AR "，" AR "，" AR "，" AR "），产品= c（" Blogger "，" Blogger "，" Google Ads "，" Web Search "，" Web Search "，" Web Search "），原因= c（" 诽谤 "，" 隐私与安全 "，" 诽谤 "，" 诽谤 "，" 其他 "，" 隐私与安全 "），总数= c（4L，1L，1L，6L，1L，8L），年= c（" 2011 "，" 2011 "，" 2011 "，" 2011 "，" 2011 "，" 2011 "）），行名= c（NA，6L），类= "数据框"）<details><summary>英文:</summary>I have a data set titled 'google_removal' with 5 columns and 14,468 rows. I am trying to expand the number of rows based on the values which specifies the frequency for observations in each row.However, I keep getting the 'undefined columns selected' error message. As far as I can see it is not a problem that stems from forgetting to add a comma and I have checked that the column in question has the particular heading I am using.Frequency is specified in the the column 'total'. It is numerical. The other variables are character. Very much a beginner here so apologies if question is poorly structured.Data looks like this. Happy to provide more if needed.'period ending' 'country' 'code' 'product' 'reason' 'total' 'year'2011-06-30 Argentina AR Blogger Defamation 4 20112011-06-30 Argentina AR Blogger Privacy 1 20112011-06-30 Argentina AR GoogleAd Defamation 1 20112011-06-30 Argentina AR WebSearch Defamation 6 2011I was trying to achieve the following:'period_ending' 'country' 'code' 'product' 'reason' 'year'2011-06-30 Argentina AR Blogger Defamation 20112011-06-30 Argentina AR Blogger Defamation 20112011-06-30 Argentina AR Blogger Defamation 20112011-06-30 Argentina AR Blogger Defamation 20112011-06-30 Argentina AR Blogger Privacy 20112011-06-30 Argentina AR GoogleAd Defamation 20112011-06-30 Argentina AR WebSearch Defamation 20112011-06-30 Argentina AR WebSearch Defamation 20112011-06-30 Argentina AR WebSearch Defamation 20112011-06-30 Argentina AR WebSearch Defamation 20112011-06-30 Argentina AR WebSearch Defamation 20112011-06-30 Argentina AR WebSearch Defamation 2011I have tried the following ('total' is the heading of the column I want to use for expanding the number of rows) adapting it from an answer to a question on expanding rows.google_removal_expanded <- google_removal[seq_len(nrow(google_removal), google_removal$total), 1:13000]google_removal_expanded <- google_removal[rep(row.names(google_removal), google_removal$total), 1:13000]I was expecting either of these to return the expanded data frame but I instead received variations of> "Error in `[.data.frame`(google_removal, rep(row.names("total"),> google_removal$total), : undefined columns selected" for both.Grateful for any assistance. My attempt to solve the problem adapted the answers inhttps://stackoverflow.com/questions/2894775/repeat-each-row-of-data-frame-the-number-of-times-specified-in-a-columnHere is some data to try it with:dput(head(google_removal))
structure(list(period_ending = c("2011-06-30", "2011-06-30",
"2011-06-30", "2011-06-30", "2011-06-30", "2011-06-30"), country = c("Argentina",
"Argentina", "Argentina", "Argentina", "Argentina", "Argentina"
), code = c("AR", "AR", "AR", "AR", "AR", "AR"), product = c("Blogger",
"Blogger", "Google Ads", "Web Search", "Web Search", "Web Search"
), reason = c("Defamation", "Privacy and Security", "Defamation",
"Defamation", "Other", "Privacy and Security"), total = c(4L,
1L, 1L, 6L, 1L, 8L), year = c("2011", "2011", "2011", "2011",
"2011", "2011")), row.names = c(NA, 6L), class = "data.frame")
答案1
得分: 1
有一个tidyr动词可用于扩展类似你的频率数据的数据：
library(tidyr)google_removal %>%uncount(total)
英文:
There is a tidyr verb for expanding frequency data such as yours:
library(tidyr)google_removal %>%uncount(total)
答案2
得分: 0
你遇到的问题是由于表达式中的 1:13000 部分引起的，因为您的数据框有 7 列（总共排除 6 列），所以如果您的数据框是这样的：
google_removal <- data.frame(period_ending = c("2011-06-30", "2011-06-30","2011-06-30", "2011-06-30", "2011-06-30", "2011-06-30"),country = c("Argentina", "Argentina", "Argentina", "Argentina", "Argentina", "Argentina"),code = c("AR", "AR", "AR", "AR", "AR", "AR"),product = c("Blogger","Blogger", "Google Ads", "Web Search", "Web Search", "Web Search"),reason = c("Defamation", "Privacy and Security", "Defamation", "Defamation", "Other", "Privacy and Security"),total = c(4L, 1L, 1L, 6L, 1L, 8L),year = c("2011", "2011", "2011", "2011", "2011", "2011"))
然后这个：
google_removal_expanded <- google_removal[rep(row.names(google_removal), google_removal$total), 1:7]
将为您提供正确的结果，行数与 total 字段中指定的一样多。
英文:
The issue you are having is due to the 1:13000 part of your expression, because your data frame has 7 columns (6 removing total), so if your data frame is:
google_removal <- data.frame(period_ending = c("2011-06-30", "2011-06-30","2011-06-30", "2011-06-30", "2011-06-30", "2011-06-30"),country = c("Argentina", "Argentina", "Argentina", "Argentina", "Argentina", "Argentina"),code = c("AR", "AR", "AR", "AR", "AR", "AR"),product = c("Blogger","Blogger", "Google Ads", "Web Search", "Web Search", "Web Search"),reason = c("Defamation", "Privacy and Security", "Defamation", "Defamation", "Other", "Privacy and Security"),total = c(4L, 1L, 1L, 6L, 1L, 8L),year = c("2011", "2011", "2011", "2011", "2011", "2011"))
Then this:
google_removal_expanded <- google_removal[rep(row.names(google_removal), google_removal$total), 1:7]
Will get you the correct result with as many rows as total field says.
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