Django FileField – 如何将文件保存到不同目录

huangapple
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英文:

Django FileField - how to save files to different directories

问题

  1. 我有两个类似的上传文件表单，但我想根据表单将文件保存在不同的目录中。
  3. 让我举个例子：
  5. 如果用户从 Form_1 上传文件 -> 文件应该保存在 ```media/folder_file_1/file.csv```
  7. 如果用户从 Form_2 上传文件 -> 文件应该保存在 ```media/folder_file_2/file.csv```
  9. 关于 ```models.py, forms.py, views.py, urls.py```，我只是在 Django 文档中使用了示例。
  11. **index.html:**
  12. ```html
  13. <!DOCTYPE html>
  14. {% load static %}
  16. <body>
  17. <div class="page_secondblock secondblock">
  18.     <div class="secondblock__container _container">
  19.         <h1 class="secondblock__title">
  20.             The file you want to update:   
  21.         </h1>
  22.         <h2 class="secondblock__title">
  23.             The file from which you want to get information:
  24.         </h2>
  25.     </div>
  26. </div>
  27. <div class="page_thirdblock thirdblock">
  28.     <div class="thirdblock__container _container">
  29.         <form method="POST" enctype="multipart/form-data" class="upload1" id="upload_container"> 
  30.             {% csrf_token %}
  31.             {{form.as_p}}
  32.             <input type="submit" value="Submit">
  33.         </form>
  34.         <form method="POST" enctype="multipart/form-data" class="upload2" id="upload_container">
  35.             {% csrf_token %}
  36.             {{form.as_p}}
  37.             <input type="submit" value="Submit">
  38.         </form>
  39.     </div>
  40. </div>
  41. </body>

models.py:

  1. from django.db import models
  3. class UploadFile(models.Model):
  4.     file = models.FileField(upload_to='working/')

forms.py:

  1. from django import forms  
  2. from .models import UploadFile
  4. class UploadFileForm(forms.ModelForm):
  5.     class Meta:
  6.         model = UploadFile
  7.         fields = ['file']

views.py:

  1. from django.shortcuts import render
  2. from django.http import HttpResponse, HttpResponseRedirect 
  3. from .forms import UploadFileForm
  4.   
  5. def index(request):
  6.     return render(request, "index.html")
  7.  
  8. def tools(request):
  9.     return render(request, "index.html")
  10.  
  11. def login(request):
  12.     return render(request, "index.html")
  14. def upload_file(request):
  15.     if request.method == 'POST':
  16.         form = UploadFileForm(request.POST,request.FILES)
  17.         if form.is_valid():
  18.             form.save()
  19.             return HttpResponseRedirect('home')    
  20.     else:
  21.         form = UploadFileForm()
  22.         context = {
  23.             'form':form,
  24.         }
  25.     return render(request, 'index.html', context)

urls.py:

  1. from django.contrib import admin
  2. from django.urls import path, re_path
  3. from actualization import views
  5. urlpatterns = [
  6.     re_path(r'^tools', views.tools, name='tools'),
  7.     re_path(r'^login', views.login, name='login'),
  8.     path('get_result/', views.get_result),
  9.     path('home/', views.upload_file, name='upload_file'),
  10. ]
英文:

I have two similar forms for upload files, but I want to save files in different directories depending on the form.

Let me explain, for example:

if User uploaded file from Form_1 -> file should be save in media/folder_file_1/file.csv

if User uploaded file from Form_2 -> file should be save in media/folder_file_2/file.csv

Regarding models.py, forms.py, views.py, urls.py I just used examples from Django docs.

index.html:

  1. &lt;!DOCTYPE html&gt;
  2. {% load static %}
  4. &lt;body&gt;
  5. &lt;div class=&quot;page_secondblock secondblock&quot;&gt;
  6.     &lt;div class=&quot;secondblock__container _container&quot;&gt;
  7.         &lt;h1 class=&quot;secondblock__title&quot;&gt;
  8.             The file you want to update:   
  9.         &lt;/h1&gt;
  10.         &lt;h2 class=&quot;secondblock__title&quot;&gt;
  11.             The file from which you want to get information:
  12.         &lt;/h2&gt;
  13.     &lt;/div&gt;
  14. &lt;/div&gt;
  15. &lt;div class=&quot;page_thirdblock thirdblock&quot;&gt;
  16.     &lt;div class=&quot;thirdblock__container _container&quot;&gt;
  17.         &lt;form method=&quot;POST&quot; enctype=&quot;multipart/form-data&quot; class=&quot;upload1&quot; id=&quot;upload_container&quot;&gt; 
  18.             {% csrf_token %}
  19.             {{form.as_p}}
  20.             &lt;input type=&quot;submit&quot; value=&quot;Submit&quot;&gt;
  21.         &lt;/form&gt;
  22.         &lt;form method=&quot;POST&quot; enctype=&quot;multipart/form-data&quot; class=&quot;upload2&quot; id=&quot;upload_container&quot;&gt;
  23.             {% csrf_token %}
  24.             {{form.as_p}}
  25.             &lt;input type=&quot;submit&quot; value=&quot;Submit&quot;&gt;
  26.         &lt;/form&gt;
  27.     &lt;/div&gt;
  28. &lt;/div&gt;
  29. &lt;/body&gt;

models.py:

  1. from django.db import models
  3. class UploadFile(models.Model):
  4.     file = models.FileField(upload_to=&#39;working/&#39;)

forms.py:

  1. from django import forms  
  2. from .models import UploadFile
  4. class UploadFileForm(forms.ModelForm):
  5.     class Meta:
  6.         model = UploadFile
  7.         fields = [&#39;file&#39;]

views.py:

  1. from django.shortcuts import render
  2. from django.http import HttpResponse, HttpResponseRedirect 
  3. from .forms import UploadFileForm
  4.   
  5. def index(request):
  6.     return render(request, &quot;index.html&quot;)
  7.  
  8. def tools(request):
  9.     return render(request, &quot;index.html&quot;)
  10.  
  11. def login(request):
  12.     return render(request, &quot;index.html&quot;)
  14. def upload_file(request):
  15.     if request.method == &#39;POST&#39;:
  16.         form = UploadFileForm(request.POST,request.FILES)
  17.         if form.is_valid():
  18.             form.save()
  19.             return HttpResponseRedirect(&#39;home&#39;)    
  20.     else:
  21.         form = UploadFileForm()
  22.         context = {
  23.             &#39;form&#39;:form,
  24.         }
  25.     return render(request, &#39;index.html&#39;, context)

urls.py:

  1. from django.contrib import admin
  2. from django.urls import path, re_path
  3. from actualization import views
  5. urlpatterns = [
  6.     re_path(r&#39;^tools&#39;, views.tools, name=&#39;tools&#39;),
  7.     re_path(r&#39;^login&#39;, views.login, name=&#39;login&#39;),
  8.     path(&#39;get_result/&#39;, views.get_result),
  9.     path(&#39;home/&#39;, views.upload_file, name=&#39;upload_file&#39;),
  10. ]

答案1

得分: 1

好的，我会翻译代码部分：

  1. from django.db import models
  3. def _upload_location(instance, filename):
  4.     return f&#39;{instance.owner.username}/{filename}&#39;
  7. class UploadFile(models.Model):
  8.     file = models.FileField(upload_to=_upload_location)
  9.     owner = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)

这样它会将文件存储在您在settings.py中分配的文件夹中作为MEDIA_ROOT。然后将其放入与您的用户名相同名称的文件夹中。然后是文件名。

英文:

Ok, so the way I do it is the following:

  1. from django.db import models
  3. def _upload_location(instance, filename):
  4.     return f&#39;{instance.owner.username}/{filename}&#39;
  7. class UploadFile(models.Model):
  8.     file = models.FileField(upload_to=_upload_location)
  9.     owner = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)

This way it stores the file inside of the folder you assigned in your settings.py as MEDIA_ROOT. Then puts it in a folder with the same name as your username. Afterwards follows the filename.

If the username as a foldername is a good choice is for sure debatable but you get the idea.

Find another good example here: FileField.upload_to

huangapple
  • 本文由 发表于 2023年6月29日 15:16:45
  • 转载请务必保留本文链接：https://go.coder-hub.com/76578811.html
  • django
  • django-file-upload
  • django-forms
  • django-models
  • python
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