英文:
Django FileField - how to save files to different directories
问题
我有两个类似的上传文件表单，但我想根据表单将文件保存在不同的目录中。
让我举个例子：
如果用户从 Form_1 上传文件 -> 文件应该保存在 ```media/folder_file_1/file.csv```
如果用户从 Form_2 上传文件 -> 文件应该保存在 ```media/folder_file_2/file.csv```
关于 ```models.py, forms.py, views.py, urls.py```，我只是在 Django 文档中使用了示例。
**index.html:**
```html
<!DOCTYPE html>
{% load static %}
<body>
<div class="page_secondblock secondblock">
<div class="secondblock__container _container">
<h1 class="secondblock__title">
The file you want to update:
</h1>
<h2 class="secondblock__title">
The file from which you want to get information:
</h2>
</div>
</div>
<div class="page_thirdblock thirdblock">
<div class="thirdblock__container _container">
<form method="POST" enctype="multipart/form-data" class="upload1" id="upload_container">
{% csrf_token %}
{{form.as_p}}
<input type="submit" value="Submit">
</form>
<form method="POST" enctype="multipart/form-data" class="upload2" id="upload_container">
{% csrf_token %}
{{form.as_p}}
<input type="submit" value="Submit">
</form>
</div>
</div>
</body>
models.py:
from django.db import models
class UploadFile(models.Model):
file = models.FileField(upload_to='working/')
forms.py:
from django import forms
from .models import UploadFile
class UploadFileForm(forms.ModelForm):
class Meta:
model = UploadFile
fields = ['file']
views.py:
from django.shortcuts import render
from django.http import HttpResponse, HttpResponseRedirect
from .forms import UploadFileForm
def index(request):
return render(request, "index.html")
def tools(request):
return render(request, "index.html")
def login(request):
return render(request, "index.html")
def upload_file(request):
if request.method == 'POST':
form = UploadFileForm(request.POST,request.FILES)
if form.is_valid():
form.save()
return HttpResponseRedirect('home')
else:
form = UploadFileForm()
context = {
'form':form,
}
return render(request, 'index.html', context)
urls.py:
from django.contrib import admin
from django.urls import path, re_path
from actualization import views
urlpatterns = [
re_path(r'^tools', views.tools, name='tools'),
re_path(r'^login', views.login, name='login'),
path('get_result/', views.get_result),
path('home/', views.upload_file, name='upload_file'),
]
英文:
I have two similar forms for upload files, but I want to save files in different directories depending on the form.
Let me explain, for example:
if User uploaded file from Form_1 -> file should be save in media/folder_file_1/file.csv
if User uploaded file from Form_2 -> file should be save in media/folder_file_2/file.csv
Regarding models.py, forms.py, views.py, urls.py I just used examples from Django docs.
index.html:
<!DOCTYPE html>
{% load static %}
<body>
<div class="page_secondblock secondblock">
<div class="secondblock__container _container">
<h1 class="secondblock__title">
The file you want to update:
</h1>
<h2 class="secondblock__title">
The file from which you want to get information:
</h2>
</div>
</div>
<div class="page_thirdblock thirdblock">
<div class="thirdblock__container _container">
<form method="POST" enctype="multipart/form-data" class="upload1" id="upload_container">
{% csrf_token %}
{{form.as_p}}
<input type="submit" value="Submit">
</form>
<form method="POST" enctype="multipart/form-data" class="upload2" id="upload_container">
{% csrf_token %}
{{form.as_p}}
<input type="submit" value="Submit">
</form>
</div>
</div>
</body>
models.py:
from django.db import models
class UploadFile(models.Model):
file = models.FileField(upload_to='working/')
forms.py:
from django import forms
from .models import UploadFile
class UploadFileForm(forms.ModelForm):
class Meta:
model = UploadFile
fields = ['file']
views.py:
from django.shortcuts import render
from django.http import HttpResponse, HttpResponseRedirect
from .forms import UploadFileForm
def index(request):
return render(request, "index.html")
def tools(request):
return render(request, "index.html")
def login(request):
return render(request, "index.html")
def upload_file(request):
if request.method == 'POST':
form = UploadFileForm(request.POST,request.FILES)
if form.is_valid():
form.save()
return HttpResponseRedirect('home')
else:
form = UploadFileForm()
context = {
'form':form,
}
return render(request, 'index.html', context)
urls.py:
from django.contrib import admin
from django.urls import path, re_path
from actualization import views
urlpatterns = [
re_path(r'^tools', views.tools, name='tools'),
re_path(r'^login', views.login, name='login'),
path('get_result/', views.get_result),
path('home/', views.upload_file, name='upload_file'),
]
答案1
得分: 1
好的，我会翻译代码部分：
from django.db import models
def _upload_location(instance, filename):
return f'{instance.owner.username}/{filename}'
class UploadFile(models.Model):
file = models.FileField(upload_to=_upload_location)
owner = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)
这样它会将文件存储在您在settings.py中分配的文件夹中作为MEDIA_ROOT。然后将其放入与您的用户名相同名称的文件夹中。然后是文件名。
英文:
Ok, so the way I do it is the following:
from django.db import models
def _upload_location(instance, filename):
return f'{instance.owner.username}/{filename}'
class UploadFile(models.Model):
file = models.FileField(upload_to=_upload_location)
owner = models.ForeignKey(settings.AUTH_USER_MODEL, on_delete=models.CASCADE)
This way it stores the file inside of the folder you assigned in your settings.py as MEDIA_ROOT. Then puts it in a folder with the same name as your username. Afterwards follows the filename.
If the username as a foldername is a good choice is for sure debatable but you get the idea.
Find another good example here: FileField.upload_to
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