英文:
Is there a way to operate each element from a list separately in order?
问题
我有一个像这样的数组列表：
[1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64]
我想逐个取出每个元素，并与其他数字进行算术运算。
代数版本是：
x^3+12x^2+48x+64
其中"x"是数组中在[i]位置的数字。
输出应该是：
[125, 216, 512, 1728, ..., -216000]
我尝试使用一个for循环，计算数组中元素的数量（在这种情况下为14），并将其用作范围。但我仍然收到“列表索引超出范围”的错误。
for i in range(numElements):
x = factors[i]
如果您需要更多信息，请告诉我。
英文:
I have an array list like this:
[1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64]
and I want to take each element one by one and operate them arithmetically with other numbers.
The algebraic version is:
x^3+12x^2+48x+64
Being "x" the number of the array in the [i] position
The output should be like:
[125, 216, 512, 1728, ..., -216000]
I tried with a for cycle counting the number of elements in the array (14 in this case) and using it as the range. But I still get the error "list index out of range".
for i in range(numElements):
x = factors[i]
Please if you need more information tell me.
答案1
得分: 2
你可以定义一个函数来执行这个操作。然后循环遍历你的列表，在每个元素上调用该函数，如下所示：
```python
def operate(num):
return num**3+12*num**2+48*num+64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64]
output = [operate(num) for num in nums]
<details>
<summary>英文:</summary>
You can define a function to perform this operation. Then loop through your list, calling that function on each element like so:
def operate(num):
return num3+12*num2+48*num+64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64]
output = [operate(num) for num in nums]
</details>
# 答案2
**得分**: 0
k = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64]
result = [x**3 + 12*x**2 + 48*x + 64 for x in k]
<details>
<summary>英文:</summary>
k=[1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64]
result=[x**3+12*x**2+48*x+64 for x in k]
</details>
# 答案3
**得分**: 0
我们可以为了方便定义一个函数，名为 `operate`。
```python
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
选项 0 - 使用 for 循环
解决这个问题的最简单方法是使用一个 for 循环，就像您打算的那样。
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64] # 您的输入列表
result = []
for num in nums:
result.append(operate(num))
如果您尝试访问超出列表长度的索引 i，可能会出现 "list index out of range" 错误。尝试使用 len(nums) 而不是手动计数。您可以编写 for 循环如下：
for i in range(len(nums)):
x = nums[i]
但如果您想更 "pythonic" 的话，最好使用上面的方法。
选项 1 - 使用列表推导式
我们可以将这个函数应用到 nums 列表的每个元素上。列表推导式文档。
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64] # 您的输入列表
result = [operate(x) for x in nums]
选项 2 - 使用 map
另一种方法是使用 map 函数，它接受要应用于可迭代对象的 函数 文档。
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64] # 您的输入列表
result = list(map(operate, nums))
选项 3 - 使用 lambda
如果您寻找一行的解决方案，可以考虑使用 lambda 函数 与 map。
result = list(map(lambda x: x ** 3 + 12 * x ** 2 + 48 * x + 64, nums))
英文:
We can define a function, operate for convenience.
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
Option 0 - Using for loop
The simplest way to solve this is to use a for loop as you intended.
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64] # your input list
result = []
for num in nums:
result.append(operate(num))
You might be getting the error, "list index out of range", if you are trying to access the index, i, which is out of the length of the list. Try using len(nums) instead of manually counting. You can write the for loop as,
for i in range(len(nums)):
x = nums[i]
But its preferred to use the above method if you want to be more "pythonic".
Option 1 - Using list comprehension
We can apply this function to each of the elements of the nums list. List comprehension documentation.
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64] # your input list
result = [operate(x) for x in nums]
Option 2 - Using map
Another method is to use the map function, which takes in the function you want to apply on the iterable documentation.
def operate(x):
return x ** 3 + 12 * x ** 2 + 48 * x + 64
nums = [1, 2, 4, 8, 16, 32, 64, -1, -2, -4, -8, -16, -32, -64] # your input list
result = list(map(operate, nums))
Operation 3 - Using lambda
If you are looking for a one-liner solution, you should consider lambda functions with map.
result = list(map(lambda x: x ** 3 + 12 * x ** 2 + 48 * x + 64, nums))
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