英文:
Regular expression. How to get strings from text?
问题
在第一种情况下，这些行位于> "\n 和 \在第二种情况下，这些行位于> message\n 和 \之间可以有任意数量的行。如何通过单个查询选择/获取这些字符串？我希望有人能够编写一个适当的正则表达式。我可以使用以下正则表达式("\n|message\n)+(.*\n.*\n)我想要的文本位于第二组中，但仅限于两行。我不知道如何编写一个适用于任意行数的表达式，以及如何添加一个以(\\n) 或 (^\\) 结束的条件。
英文:
There is a text:
"Sample text 1!,,Sample&.,? text 2?\-message32 Another sample text 3... sample text 4&!Sample text 5%\
https://regex101.com/r/LwySuM/1
In the first case, the lines are between
> "\n and \
In the second, the lines are between
> message\n and \
There can be any number of lines in between.
How can I select/get these strings in a single query?
I hope someone will write a proper regular expression.
I can do this
("\n|message\n)+(.*\n.*\n)
The text I want is in the second group but it's only for two lines. I don't know how to write a expression for any number of lines and how to add a condition that ends with
(\\n) or (^\\)
答案1
得分: 0
> _"... 我想要的文本在第二组，但只有两行。我不知道如何写一个适用于任意行数的表达式 ..."_你正在寻找 _单行_ 模式，即 `s`。在这种模式下，`.` 会匹配换行符。这里的 `\s+?^` 用于跳过换行符，以便它们不在 _捕获组_ 内。```none/(?:-message|")\s+?^(.+?)\s+?^\\/gms
英文:
> "... The text I want is in the second group but it's only for two lines. I don't know how to write a expression for any number of lines ..."
You are looking for single-line mode, s.
This is where a . will additionally match new-line delimiters.
The \s+?^ here is used to skip-over the new-line delimiters, so they are not within the capture group.
/(?:-message|")\s+?^(.+?)\s+?^\\/gms
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