英文:
Api for deleting
问题
const deleteContact = asyncHandler(async (req, res) => {const contact = await Contact.findById(req.params.id);if (!contact) {res.status(404);throw new Error("联系人未找到");}await Contact.remove();res.status(200).json();});
英文:
const deleteContact=asyncHandler(async(req,res)=>{const contact=await Contact.findById(req.params.id);if(!contact){res.status(404);throw new Error("Contact Not foud");}await Contact.remove();res.status(200).json();});
I'm trying to write the end point of the deleting contact but I'm not able to delete by using the above query.
答案1
得分: 0
> MongoDB驱动程序的remove()函数已被弃用，建议使用
> deleteOne() 和 deleteMany()。这是为了符合MongoDB CRUD
> 规范，该规范旨在为所有MongoDB驱动程序的CRUD
> 操作提供一致的API。
因此，使用deleteOne而不是remove，如下所示：
await Contact.deleteOne({ _id: req.params.id });
更新后的代码：
const deleteContact = asyncHandler(async(req, res) => {const contact = await Contact.findById(req.params.id);if (!contact) {res.status(404);throw new Error("联系人未找到");}await Contact.deleteOne({ _id: req.params.id });res.status(200).json();});
英文:
As per mongoose v7.3.1 document:
> The MongoDB driver's remove() function is deprecated in favor of
> deleteOne() and deleteMany(). This is to comply with the MongoDB CRUD
> specification, which aims to provide a consistent API for CRUD
> operations across all MongoDB drivers.
So use deleteOne instead of remove, as:
await Contact.deleteOne({ _id: req.params.id });
Updated code:
const deleteContact = asyncHandler(async(req,res) => {const contact=await Contact.findById(req.params.id);if(!contact){res.status(404);throw new Error("Contact Not found");}await Contact.deleteOne({ _id: req.params.id });res.status(200).json();});
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