How to test if array elements are all equal in bash?

I wrote a script that checks if the user of the wheel group is on the list of allowed users, if true then writes the value 0 in the list result, if false then 1. Then I found a piece of code that checks if all values in the result list are the same. My problem is that when none of the users are on the list they all get 1 and this makes the test pass and it should fail

What do I need? Help with code review to make the test work for cases:

result=(all members are 0) test pass

result=(minimum one member has 1) test fail

result=(all members are 1) test fail

#!/bin/bash
source ./colorama.conf

message="verify group wheel members"
wheel_members_list=(
    "username_01"
    "username_02"
    "username_03"
    )
#echo ${wheel_members_list[@]}

output=`getent group wheel | awk -F: '{print $4}' | tr , '\n'`
#echo $output

result=()

for username in $output;do
    if [[ ${wheel_members_list[@]} =~ (^|[[:space:]])$username($|[[:space:]]) ]];then
        result+=(0)
    else
        result+=(1)
    fi
done

echo state: ${result[@]}

if [ "${#result[@]}" -gt 0 ] && [ $(printf "%s
#!/bin/bash
source ./colorama.conf
message="verify group wheel members"
wheel_members_list=(
"username_01"
"username_02"
"username_03"
)
#echo ${wheel_members_list[@]}
output=`getent group wheel | awk -F: '{print $4}' | tr , '\n'`
#echo $output
result=()
for username in $output;do
if [[ ${wheel_members_list[@]} =~ (^|[[:space:]])$username($|[[:space:]]) ]];then
result+=(0)
else
result+=(1)
fi
done
echo state: ${result[@]}
if [ "${#result[@]}" -gt 0 ] && [ $(printf "%s\000" "${result[@]}" | 
LC_ALL=C sort -z -u |
grep -z -c .) -eq 1 ] ; then
echo pass
exit 0
else
echo fail
exit 1
fi
0" "${result[@]}" | 
       LC_ALL=C sort -z -u |
       grep -z -c .) -eq 1 ] ; then
    echo pass
    exit 0
else
  echo fail
  exit 1
fi

EDIT: for the moment i solved it with if condition, but i will appreciate help with the first version

for state in ${result[@]}; do
    if [ $state -eq 1 ]; then
        exit 1
    fi
done
exit 0

Since result is an array of only 0's and 1's, you can do this most efficiently by using pure bash:

if [[ "${result[*]}" =~ 1 ]]; then
    echo fail
else
    echo pass
fi

This way is less efficient but more in line with what you were trying, you just gotta use the fact that grep fails if it finds no match:

if printf "%s
if printf "%s\0" "${result[@]}" |  grep -zq 1; then
echo fail
else
echo pass
fi
" "${result[@]}" |  grep -zq 1; then
    echo fail
else
    echo pass
fi