英文:
How do I print lines in between two searches
问题
你的脚本中有一些问题，导致它只打印了以pat1开头的一行。以下是修复后的脚本：
import os
import re
pat1 = r"FEATURE AAA"
pat2 = r"[^\\]"$"
with open('all.txt') as f:
inside_feature = False
for line in f:
if re.search(pat1, line):
inside_feature = True
print(line, end='')
continue
if inside_feature and not re.search(pat2, line):
print(line, end='')
if inside_feature and re.search(pat2, line):
inside_feature = False
f.close()
这个修复后的脚本应该可以正确打印位于pat1和pat2之间的行，其中pat1行以"FEATURE AAA"开头，而pat2行不以\"结尾。
英文:
My text as follows:
FEATURE AAA cdslmd 22.02 28-jul-2023 1 \
3F76BA3DA7102935AD12 VENDOR_STRING=J:PERM DUP_GROUP=NONE \
vendor_info=13-jun-2023 \
ISSUER=CDNS2161b9360e2037d6f7bd35a11244661a ISSUED=13-jun-2023 \
EC0C" V7.1_LK=3F06FAFDD30D943EC2DD
FEATURE BBB cdslmd 22.02 28-jul-2023 2 7F061A2D977BFEF08F2F \
VENDOR_STRING=J:PERM DUP_GROUP=NONE vendor_info=13-jun-2023 \
ISSUER=CDNS2161b9360e2037d6f7bd35a11244661a ISSUED=13-jun-2023 \
A843" V7.1_LK=BFC68A9D5606A8296604
Expected result:
FEATURE AAA cdslmd 22.02 28-jul-2023 1 \
3F76BA3DA7102935AD12 VENDOR_STRING=J:PERM DUP_GROUP=NONE \
vendor_info=13-jun-2023 \
ISSUER=CDNS2161b9360e2037d6f7bd35a11244661a ISSUED=13-jun-2023 \
EC0C" V7.1_LK=3F06FAFDD30D943EC2DD
My script:
import os
import re
pat1 = r"[A-Z]+.AAA"
pat2 = r"[^\\]$"
with open('all.txt') as f:
match = False
for l in f:
if re.match(pat1, l):
match = True
print (l)
continue
if re.search(pat2, l):
match = False
continue
if match:
print (l)
f.close()
Outcome of above script:
FEATURE AAA cdslmd 22.02 28-jul-2023 1 1F469A0DE7A48BDAE16B \
It is printing only one line that starts with pat1. I wanted to print lines between pat1 and pat2 (where the end of line does not end with "" after pat1).
答案1
得分: 1
r"[^\\]$" 将匹配每行末尾的换行符 (\n)。不过，您不需要正则表达式来进行这个检查，您可以简单地这样做：
if not l.strip().endswith('\\'):
match = False
continue
另外，为了获得您期望的输出，即也打印不以 \ 结尾的行，您需要交换您的 if 语句的顺序：
if re.match(pat1, l):
match = True
print(l)
continue
if match:
print(l)
if not l.strip().endswith('\\'):
match = False
continue
另一种方法是，pattern2 也可以是 r"[^\\]\n$"，但我觉得第一种方法更容易阅读。
英文:
r"[^\\]$" will match the newline character (\n) at the end of every line. You don't need a regex for that check though, you can simply do
if not l.strip().endswith('\\'):
match = False
continue
Additionally, to get your desired output, i.e. also print the line that does not end with \, you will need to switch the order of your if statements:
if re.match(pat1, l):
match = True
print (l)
continue
if match:
print (l)
if not l.strip().endswith('\\'):
match = False
continue
Alternatively, pattern2 could also be r"[^\\]\n$", but I feel like the first approach is easier to read
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