英文:
Better way to create query string dynamically
问题
Sure, here's the translated code part:
我收到一个可能如下所示的查询参数对象：const queryParams = { status: 'Online', name: 'Jeff', age: '35' }我需要将其转换为查询参数字符串，示例返回值将是：?status=Online&name=Jeff&age=35&我编写了以下函数：const getParams = (queryParams) => {let str = '?'for (key in queryParams) {if (queryParams[key]) {str += `${key}=${queryParams[key]}&`}}return str};是否有比这个函数更短/更好的方法？
Please note that I've translated the code and the relevant text while omitting the parts you requested not to be translated.
英文:
I'm getting a query params object that may look like this:
const queryParams = { status: 'Online', name: 'Jeff', age: '35' }
I need to create a query params string out of it,
Example return value would be:
?status=Online&name=Jeff&age=35&
I wrote this function:
const getParams = (queryParams) => {let str = '?'for (key in queryParams) {if (queryParams[key]) {str+= `${key}=${queryParams[key]}&`}}return str};
Is there a shorter/better way to do it than this function?
答案1
得分: 1
const queryParams = { status: '在线', name: 'Jeff', age: '35' };function buildQueryString(params) {const queryString = Object.entries(params).map(([key, value]) => `${key}=${value}`).join('&');return queryString;}const queryString = buildQueryString(queryParams);
英文:
const queryParams = { status: 'Online', name: 'Jeff', age: '35' };function buildQueryString(params) {const queryString = Object.entries(params).map(([key, value]) => `${key}=${value}`).join('&');return queryString;}const queryString = buildQueryString(queryParams);
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