英文:
Find max time difference within each year in R
问题
这是您要翻译的内容:
"I have a function that calculates the average, min and max values for each year in my dataframe, then merges them to output the alltime average, min and max values. Each year needs to be calculated separately first because my dates only refer to the months of April through August. If I didn't group it by year, there would be calculations between August of one year and April of the next year. I want to avoid this.
Example dataframe:
date NDVI cloud_cover field_id
23/04/2017 0.6494 12 KM60
23/04/2017 0.5683 0 KM1
05/05/2017 0.3467 0 KM60
31/07/2017 0.6743 05 KM60
31/07/2017 NA 97 KM1
31/07/2017 0.3456 07 LM27
01/04/2018 NA 100 KM60
03/06/2018 0.6743 11 KM60
03/06/2018 0.2346 12 KM1
04/05/2019 NA 99 KM60
05/05/2019 0.5432 20 KM60
NDVI and cloud_cover shouldn't influence calculations. Although field_ids most times provide the same dates, this also shouldn't influence them.
This is the current code:
calculate_time_diff <- function(df) {
# Convert "date" column to datetime
df$date <- as.POSIXct(df$date)
# Group the data by year
df_calc <- split(df, format(df$date, "%Y"))
# Calculate time differences between consecutive observations for each year
time_diffs <- lapply(df_calc, function(group) {
# Sort dataframe based on "date"
group <- group[order(group$date), ]
# Filter out duplicate dates
group <- group[!duplicated(group$date), ]
# Calculate time differences between consecutive observations
diff(group$date)
})
# Combine time differences from all years into a single vector
all_time_diffs <- unlist(time_diffs)
# Compute average time difference
avg_time_diff <- mean(all_time_diffs)
# Calculate smallest and biggest time differences
smallest_time_diff <- min(all_time_diffs)
biggest_time_diff <- max(all_time_diffs)
return(list(avg_time_diff = avg_time_diff,
smallest_time_diff = smallest_time_diff,
biggest_time_diff = biggest_time_diff))
}
The output is giving me "240" as max time difference, which I know to be unrealistic. My dataframe refers to the revisit dates of three satellites and none of them should be more than at the very most a month apart.
I thought it could have something to do with the way years are being extracted, but this user seems to have successfully used format() just as I did. lapply() should iterate through each split year group in the same way as group_by(). So what could be the problem in my script?"
英文:
I have a function that calculates the average, min and max values for each year in my dataframe, then merges them to output the alltime average, min and max values. Each year needs to be calculated separately first because my dates only refer to the months of April through August. If I didn't group it by year, there would be calculations between August of one year and April of the next year. I want to avoid this.
Example dataframe:
date NDVI cloud_cover field_id
23/04/2017 0.6494 12 KM60
23/04/2017 0.5683 0 KM1
05/05/2017 0.3467 0 KM60
31/07/2017 0.6743 05 KM60
31/07/2017 NA 97 KM1
31/07/2017 0.3456 07 LM27
01/04/2018 NA 100 KM60
03/06/2018 0.6743 11 KM60
03/06/2018 0.2346 12 KM1
04/05/2019 NA 99 KM60
05/05/2019 0.5432 20 KM60
NDVI and cloud_cover shouldn't influence calculations. Although field_ids most times provide the same dates, this also shouldn't influence them.
This is the current code:
calculate_time_diff <- function(df) {
# Convert "date" column to datetime
df$date <- as.POSIXct(df$date)
# Group the data by year
df_calc <- split(df, format(df$date, "%Y"))
# Calculate time differences between consecutive observations for each year
time_diffs <- lapply(df_calc, function(group) {
# Sort dataframe based on "date"
group <- group[order(group$date), ]
# Filter out duplicate dates
group <- group[!duplicated(group$date), ]
# Calculate time differences between consecutive observations
diff(group$date)
})
# Combine time differences from all years into a single vector
all_time_diffs <- unlist(time_diffs)
# Compute average time difference
avg_time_diff <- mean(all_time_diffs)
# Calculate smallest and biggest time differences
smallest_time_diff <- min(all_time_diffs)
biggest_time_diff <- max(all_time_diffs)
return(list(avg_time_diff = avg_time_diff,
smallest_time_diff = smallest_time_diff,
biggest_time_diff = biggest_time_diff))
}
The output is giving me "240" as max time difference, which I know to be unrealistic. My dataframe refers to the revisit dates of three satellites and none of them should be more than at the very most a month apart.
I thought it could have something to do with the way years are being extracted, but this user seems to have successfully used format() just as I did. lapply() should iterate through each split year group in the same way as group_by(). So what could be the problem in my script?
答案1
得分: 0
Using dplyr:
data %>%
distinct(date) %>%
arrange(date) %>%
group_by(format(date, "%Y")) %>%
reframe(dateDiff = diff(date)) %>%
with(list(avg_time_diff = mean(dateDiff),
smallest_time_diff = min(dateDiff),
biggest_time_diff = max(dateDiff)))
Result:
$avg_time_diff
Time difference of 30.02198 days
$smallest_time_diff
Time difference of 12 days
$biggest_time_diff
Time difference of 51 days
Dummy data:
data <- data.frame(date = seq(as.Date("2017-01-01"), by = "month", length.out = 100) + sample(0:20, 100, TRUE))
英文:
Using dplyr:
data %>%
distinct(date) %>% #remove duplicates
arrange(date) %>% #order by date
group_by(format(date, "%Y")) %>% #group by year
reframe(dateDiff = diff(date)) %>% #apply 'diff' to every group
with(list(avg_time_diff = mean(dateDiff),
smallest_time_diff = min(dateDiff),
biggest_time_diff = max(dateDiff))) #create your metrics
Result:
$avg_time_diff
Time difference of 30.02198 days
$smallest_time_diff
Time difference of 12 days
$biggest_time_diff
Time difference of 51 days
Dummy data:
data <- data.frame(date = seq(as.Date("2017-01-01"), by = "month", length.out = 100) + sample(0:20, 100, TRUE))
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