英文:
Flushing output while program runs from bash
问题
我对Bash脚本不太熟悉，所以请耐心等待。
我有一个类似这样的小脚本：
readarray -t lines < <($COMMAND)
for line in "${lines[@]}"; do
echo $line
theLines+="$line\n"
done
当$COMMAND尚未完成时，STDOUT上肯定不会有任何输出。
它可以是ls -la，unzip或其他任何命令。
如何实时打印命令的输出？
英文:
I am not so familiar with bash scripts, so please be patient with me.
I have a little script like this:
readarray -t lines < <($COMMAND)
for line in "${lines[@]}"; do
echo $line
theLines+="$line\n"
done
Surely nothing will be on STDOUT while $COMMAND not finished.
It could be an ls -la, unzip whatever.
How can I print the output of command real time?
答案1
得分: 1
不要首先将输出存储在数组中。让循环直接从命令中读取。readarray 必须等到读取完所有输出才能完成。
while read -r line; do
echo "$line"
theLines+="$line"$'\n'
done < <($COMMAND)
如果你真的想要将其存储在数组中，你可以在循环中向数组添加内容。
while read -r line; do
echo "$line"
theLines+="$line"$'\n'
lines+=("$line")
done < <($COMMAND)
还请注意，你必须使用 $'\n' 来获得 theLines 中的换行符。转义序列不会在双引号内展开。
英文:
Don't store the output in an array first. Have the loop read from the command itself. readarray can't finish until it had read all the output.
while read -r line; do
echo "$line"
theLines+="$line"$'\n'
done < <($COMMAND)
If you really want it in an array, you can add to the array in the loop.
while read -r line; do
echo "$line"
theLines+="$line"$'\n'
lines+=("$line")
done < <($COMMAND)
Note also that you have to use $'\n' to get a newline in theLines. Escape sequences aren't expanded inside double quotes.
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