在JavaScript中,获取数组对象中与键对应的唯一值

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英文:

Get unique values corresponding to the keys from an array of objects in JavaScript

问题

我的数组如下所示:

const arr1 = [
  {
    "Param1": "20",
    "Param2": "8",
    "Param3": "11",
    "Param4": "4",
    "Param5": "18",
    "Param6": "20",
    "Param7": "8"
  },
  {
    "Param6": "21",
    "Param7": "8",
    "Param8": "11",
    "Param9": "4",
    "Param10": "18"
  },
  {
    "Param1": "20",
    "Param2": "8",
    "Param3": "10"
  }
]

我想要删除对象中存在的重复键值对。
期望结果:

arr1 = [
  {
    "Param1": "20",
    "Param2": "8",
    "Param3": "11",
    "Param4": "4",
    "Param5": "18",
    "Param6": "20",
    "Param7": "8"
  },
  {
    "Param6": "21",
    "Param8": "11",
    "Param9": "4",
    "Param10": "18"
  },
  {
    "Param3": "10"
  }
]

期望的输出是一个包含具有唯一键值对的对象的数组。如何获得这样的数组?

英文:

My array looks like this

const arr1 = [
  {
    "Param1": "20",
    "Param2": "8",
    "Param3": "11",
    "Param4": "4",
    "Param5": "18",
    "Param6": "20",
    "Param7": "8"
  },
  {
    "Param6": "21",
    "Param7": "8",
    "Param8": "11",
    "Param9": "4",
    "Param10": "18"
  },
  {
    "Param1": "20",
    "Param2": "8",
    "Param3": "10"
  }
]

I wanted to remove the duplicate key value pairs existing in the objects.
Expected result:

arr1 = [
  {
    "Param1": "20",
    "Param2": "8",
    "Param3": "11",
    "Param4": "4",
    "Param5": "18",
    "Param6": "20",
    "Param7": "8"
  },
  {
    "Param6": "21",
    "Param8": "11",
    "Param9": "4",
    "Param10": "18"
  },
  {
    "Param3": "10"
  }
]

The desired output is an array containing objects having unique key value pairs. How can I get such an array?

答案1

得分: 2

Algorithm:

  • 创建一个以{param: {value: boolean}}格式的seen映射,用于指示是否已经看到具有这个值的参数。
  • 创建一个result数组,用于存储唯一的参数。
  • 遍历输入数组,获取当前元素的键,并遍历这些键。
  • 检查具有这个值的参数是否已经被看到,如果是,则忽略它;否则将其添加到result中并标记为已看到。
  • 返回result数组。

Implementation:

const removeDuplicates = (arr) => {
    return arr.reduce(
        (acc, item) => {
            acc.result.push(
                Object.fromEntries(
                    Object.entries(item).filter(([key, value]) => {
                        acc.seen[key] = acc.seen[key] ?? {};
                        if (acc.seen[key][value]) return false;
                        acc.seen[key][value] = true;

                        return true;
                    }),
                ),
            );
            return acc;
        },
        { seen: {}, result: [] },
    ).result;
};

playground

英文:

Algorithm:

  • Create a map seen in the format of {param: {value: boolean}} which will indicate whether the param with this value was already seen
  • Create a result array that will store the unique params
  • Traverse through the input array, get the keys of the current element, and traverse through them.
  • Check if the param with this value was already seen, if yes, ignore it; otherwise add it to the result and mark it as seen
  • Return the result array.

Implementation:

const removeDuplicates = (arr: Record<string, string>[]) => {
    return arr.reduce<{
        seen: Record<string, Record<string, boolean>>;
        result: Record<string, string>[];
    }>(
        (acc, item) => {
            acc.result.push(
                Object.fromEntries(
                    Object.entries(item).filter(([key, value]) => {
                        acc.seen[key] = acc.seen[key] ?? {};
                        if (acc.seen[key][value]) return false;
                        acc.seen[key][value] = true;

                        return true;
                    }),
                ),
            );
            return acc;
        },
        { seen: {}, result: [] },
    ).result;
};

playground

huangapple
  • 本文由 发表于 2023年6月22日 17:23:04
  • 转载请务必保留本文链接:https://go.coder-hub.com/76530384.html
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