英文:
javascript fetch is fired double
问题
Sure, here's the translation of the code portion you provided:
我有一个简单的JavaScript函数,用于获取URL并在收到响应时更新HTML页面,如下所示:
function post_db(self) {
// 其他代码在这里
async function postData() {
const url = "fetchnewseq";
const response = await fetch(url, {
method: 'POST',
headers: {
'X-CSRFToken': csrftoken,
'Content-Type': 'application/json'
},
body: JSON.stringify(comandi_json)
});
return await response.json()
}
postData().then((data) => {
window.location.replace(data.url);
});
}
post_db函数由按钮触发,如下所示:
<button onclick="post_db(this)" class="btn btn-success">Conferma</button>
在后端,我使用Django,管理该URL的视图如下:
def fetch_new_seq(request):
json_received = json.loads(request.body.decode("utf-8"))
print(json_received)
messages.success(request, "Ricevuto")
redirect_url = reverse('newSeq')
return JsonResponse({'url': redirect_url})
此外,我看到fetch请求两次触发,我无法理解为什么会发生,因为按钮只被点击了一次。我还在Mozilla浏览器的控制台中看到了错误Uncaught (in promise) TypeError: NetworkError when attempting to fetch resource.
触发post_db的按钮位于一定数量的
Creazione di sequenze di movimento
<div class="row">
<div class="d-grid gap-2 col">
<button onclick="load_js()" class="btn btn-secondary">
Riordina
</button>
</div>
<div class="d-grid gap-2 col">
{% csrf_token %}
<button onclick="post_db()" class="btn btn-success">
Conferma
</button>
</div>
<div class="d-grid gap-2 col">
<button onclick="addNewRow()" class="btn btn-primary">
Aggiungi Movimento
</button>
</div>
</div>
```
Please note that the code you provided seems to contain HTML entities like "
and >
, which are typically used for encoding double quotes and greater-than signs in HTML. These entities should be decoded when using the code, but I've left them as is in the translation for clarity.
英文:
I have a simple function in javascript that fetch and URL and update the HTML page when it got a response like:
function post_db(self) {
// other code here
async function postData() {
const url = "fetchnewseq"
const response = await fetch(url, {
method: 'POST',
headers: {
'X-CSRFToken': csrftoken,
'Content-Type': 'application/json'
},
body: JSON.stringify(comandi_json)
});
return await response.json()
}
postData().then((data) => {
window.location.replace(data.url);
});
}
The post_db function is fired by a button like
<button onclick="post_db(this)" class="btn btn-success">Conferma</button>
On the backend I'm using Django and the view that manages that URL is
def fetch_new_seq(request):
json_ricevuto = json.loads(request.body.decode("utf-8"))
print(json_ricevuto)
messages.success(request, "Ricevuto")
redirect_url = reverse('newSeq')
return JsonResponse({'url': redirect_url})
For some reason, the fetch is fired two times as I'm seeing the function on the backed with the same results two times
I can't understand why it happens tho as, the button is clicked just one
I'm also seeing on the console of Mozilla Browser I got the error Uncaught (in promise) TypeError: NetworkError when attempting to fetch resource.
The button that fires the post_db is inside a certain number of divs
<div id="container" class="container-fluid">
<div class="container text-center">
<h3>Creazione di sequenze di movimento</h3>
<input
type="text"
class="form-control mt-3 mb-3"
id="titleseq"
placeholder="Inserisci Titolo"
/>
<div class="row">
<div class="d-grid gap-2 col">
<button onclick="load_js()" class="btn btn-secondary">
Riordina
</button>
</div>
<div class="d-grid gap-2 col">
{% csrf_token %}
<button onclick="post_db()" class="btn btn-success">
Conferma
</button>
</div>
<div class="d-grid gap-2 col">
<button onclick="addNewRow()" class="btn btn-primary">
Aggiungi Movimento
</button>
</div>
</div>
</div>
答案1
得分: 0
我可能已经找到了问题所在。具有fetch
代码的async
函数位于像下面这样的for
循环中:
for (var i = 0; i < len_array; i++) {
if (
comandi_json["lista_comandi"][i]["comando"] == "" ||
comandi_json["lista_comandi"][i]["tempo"] == null
) {
console.log("Error");
return;
} else {
async function postData() {
const url = "fetchnewseq";
const response = await fetch(url, {
method: "POST",
headers: {
"X-CSRFToken": csrftoken,
"Content-Type": "application/json",
},
body: JSON.stringify(comandi_json),
});
return await response.json();
}
postData().then((data) => {
window.location.replace(data.url);
});
}
}
很明显,每次第一个检查正确执行而没有return
时,else
就会被触发,并且随之触发了fetch
函数多次,从而引发了问题。
将其重写到循环外部修复了问题:
for (var i = 0; i < len_array; i++) {
if (
comandi_json["lista_comandi"][i]["comando"] == "" ||
comandi_json["lista_comandi"][i]["tempo"] == null
) {
console.log("Error");
return;
}
}
async function postData() {
const url = "fetchnewseq";
const response = await fetch(url, {
method: "POST",
headers: {
"X-CSRFToken": csrftoken,
"Content-Type": "application/json",
},
body: JSON.stringify(comandi_json),
});
return await response.json();
}
postData().then((data) => {
window.location.replace(data.url);
});
英文:
So I may have found the issue. The async
function with the fetch
code was inside a for
loop like:
for (var i = 0; i < len_array; i++) {
if (
comandi_json["lista_comandi"][i]["comando"] == "" ||
comandi_json["lista_comandi"][i]["tempo"] == null
) {
console.log("Error");
return;
} else {
async function postData() {
const url = "fetchnewseq";
const response = await fetch(url, {
method: "POST",
headers: {
"X-CSRFToken": csrftoken,
"Content-Type": "application/json",
},
body: JSON.stringify(comandi_json),
});
return await response.json();
}
postData().then((data) => {
window.location.replace(data.url);
});
}
}
Clearly, every time the first check was performed correctly without return
, the else
got fired and, with it, the fetch
function triggered it more than once and generated the issue.
Rewriting it outside the for fixed the issue
for (var i = 0; i < len_array; i++) {
if (
comandi_json["lista_comandi"][i]["comando"] == "" ||
comandi_json["lista_comandi"][i]["tempo"] == null
) {
console.log("Error");
return;
}
}
async function postData() {
const url = "fetchnewseq";
const response = await fetch(url, {
method: "POST",
headers: {
"X-CSRFToken": csrftoken,
"Content-Type": "application/json",
},
body: JSON.stringify(comandi_json),
});
return await response.json();
}
postData().then((data) => {
window.location.replace(data.url);
});
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