How to find 2 integers that can form the numerical values of a list and structure the answers in another list?

#Given the following 2 example tables (always both tables have the same dimensions)

tabla_ganancias = [[5, 6, 3, 5, 5], 
                   [2, 5, 3, 1, 0], 
                   [2, 4, 0, 1, 1]]

tabla_asignaciones = [[ 140,  220, None,   80,   60], 
                      [None, None,  330, None, None], 
                      [None, None,   30, None,   90]]

tabla_resultado = []
rows = len(tabla_ganancias)
columns = len(tabla_ganancias[0])

#Code that creates result_table and does the decomposition of the profits
#HERE THE PROBLEM

#Print the results obtained
print(tabla_resultado)
for lista in tabla_resultado: print(lista)

I decompose the values of tabla_ganancias that correspond to the non-empty cells (that is, they are not None) of tabla_assignments, placing the decomposition of the values of the earnings in the last of the rows and in the last of the columns .

In this case, the values of the profits would be broken down (by breaking down I mean finding 2 integers that add up to form):

The gain value 5 become in 2 in a row and 3 in a column ---> 2 + 3 = 5

The gain value 6 become in 2 in a row and 4 in a column ---> 2 + 4 = 6

The gain value 5 become in 2 in a row and 3 in a column ---> 2 + 3 = 5

The gain value 5 become in 2 in a row and 3 in a column ---> 2 + 3 = 5

The gain value 3 become in 1 in a row and 2 in a column ---> 1 + 2 = 3

The gain value 0 become in 2 in a row and -2 in a column ---> 2 + (-2) = 0

The gain value 1 become in -2 in a row and 3 in a column ---> -2 + 3 = 1

So that there is a resulting table having in its last row and its last column the decomposition of the profits. Note that tabla_resultado is the tabla_asignaciones but with the row and column of the decompositions of the profits

#The decomposed values will be stored in the last row and last column of tabla_resultado.


#System of equations that should be solved to find the values that I need to build the last of the rows and the last of the columns of tabla_resultado
# X1 + Y1 = 5
# X2 + Y1 = 6
# X4 + Y1 = 5
# X5 + Y1 = 5
# X3 + Y2 = 3
# X3 + Y3 = 0
# X5 + Y3 = 1

#tabla_resultado = [[ 140,  220, None,   80,   60,    Y1], 
#                   [None, None,  330, None, None,    Y2], 
#                   [None, None,   30, None,   90,    Y3], 
#                   [  X1,   X2,   X3,   X4,   X5,  None]]

tabla_resultado = [[ 140,  220, None,   80,   60,    2], 
                   [None, None,  330, None, None,    1], 
                   [None, None,   30, None,   90,   -2], 
                   [   3,    4,    2,    3,    3, None]]

This code not work, but I add this

#Given the following 2 example tables (always both tables have the same dimensions)

tabla_ganancias = [[5, 6, 3, 5, 5], 
                   [2, 5, 3, 1, 0], 
                   [2, 4, 0, 1, 1]]

tabla_asignaciones = [[ 140,  220, None,   80,   60], 
                      [None, None,  330, None, None], 
                      [None, None,   30, None,   90]]


tabla_resultado = []
rows = len(tabla_ganancias)
columns = len(tabla_ganancias[0])

for i in range(rows):
    tabla_resultado.append([])
    for j in range(columns):
        if tabla_asignaciones[i][j] is not None:
            value = tabla_ganancias[i][j]
            x = value // 2
            y = value - x
            tabla_resultado[i].append(x)
            if len(tabla_resultado) <= j+rows:
                tabla_resultado.append([None] * (rows+1))
            tabla_resultado[i][j+rows] = y
        else:
            tabla_resultado[i].append(None)

# Print the results obtained
print(tabla_resultado)
for lista in tabla_resultado: print(lista)

But I get that error

Traceback (most recent call last):
    tabla_resultado[i][j+rows] = y
IndexError: list assignment index out of range

Become the problem to System of Linear Equations

The answer is not to fix the IndexError in your code, but to achieve your desired output. And also when you try to create a list of None, avoid using [None] * n, refer to this answer : List of lists changes reflected across sublists unexpectedly.

Here is the code, I have added some comments :

rows = len(tabla_ganancias)
columns = len(tabla_ganancias[0])
# Append a None for each row 
[tabla_asignaciones[t].append(None) for t in range(rows)]

# Append a list of None as the last row
add_row_list = [None for t in range(columns+1)]
tabla_asignaciones.append(add_row_list)

for i in range(rows):
    for j in range(columns):
        # Check if is None in tabla_asignaciones
        if tabla_asignaciones[i][j] is not None:
            value = tabla_ganancias[i][j]
            
            # If don't have value in X and Y
            if add_row_list[j] is None and tabla_asignaciones[i][columns] is None:
                x = value // 2
                y = value - x
                tabla_asignaciones[rows][j] = y
                tabla_asignaciones[i][columns] = x
            # If don't have value in X but have value in  Y
            elif add_row_list[j] is None and  not tabla_asignaciones[i][columns] is None:
                tabla_asignaciones[rows][j] = value - tabla_asignaciones[i][columns]
            # If have value in X but don't have value in  Y
            elif not add_row_list[j] is None and tabla_asignaciones[i][columns] is None:
                tabla_asignaciones[i][columns] = value - tabla_asignaciones[rows][j]

The result is tabla_asignaciones:

> [[140, 220, None, 80, 60, 2],
>
> [None, None, 330, None, None, 1],
>
> [None, None, 30, None, 90, -2],
>
> [3, 4, 2, 3, 3, None]]