Import XML with a non typical format to a class

I need to import a XML file looking like this:

<Carpark>
   <Trucks>
      <Truck brand='Chrysler' kg='2100'/>
   </Trucks>
   <Cars>
      <Car brand='Mercedes' kg='1100'/>
   </Cars>
   <Tractors>
      <Tractor brand='John Deere' kg='1500'/>
   </Tractors>
</Carpark>

Essentially I want to have a list of Carpark like this:

public class Carpark
{
    // Type can be for example Truck, Car
    public string Type { get; set; }
    public string Brand { get; set; }
    public int Weight { get; set; }
}

I don't understand how to convert this XML file to the class I want.

What I have tried is:

XElement xElement = XElement.Load(filePath);
IEnumerable<Carpark> carpark = xElement.Elements();

foreach(var vehicle in carpark)
{
    // Once I wrote out the line I was confused as to how to proceed
    Console.WriteLine(vehicle.ToString());
}

You can do that with Linq_To_XML and I believe with NewtonsoftJSON:

void Main()
{
	var xml = XElement.Parse(x)
		.DescendantsAndSelf("Carpark")
		.Descendants()
		.Where(xe => xe.HasAttributes)
		.Select(xe => new Carpark {
			Type = xe.Name.ToString(),
			Brand = (string)xe.Attribute("brand"),
			Weight = (int)xe.Attribute("kg")
		})
		;
		
	foreach (var cp in xml)
	{
		Console.WriteLine($"{cp.Type}, {cp.Brand}, {cp.Weight}");
	}
	
}

static readonly string x = @"<Carpark>
   <Trucks>
      <Truck brand='Chrysler' kg='2100'/>
   </Trucks>
   <Cars>
      <Car brand='Mercedes' kg='1100'/>
   </Cars>
   <Tractors>
      <Tractor brand='John Deere' kg='1500'/>
   </Tractors>
</Carpark>";

public class Carpark
{
	// Type can be for example Truck, Car
	public string Type { get; set; }
	public string Brand { get; set; }
	public int Weight { get; set; }
}

You can use the following classes to deserialize this with XmlSerializer automatically

public class Carpark
{
	public List<Truck> Trucks { get; set; }
	public List<Car> Cars { get; set; }
	public List<Tractor> Tractors { get; set; }
}

[XmlInclude(typeof(Truck))]
[XmlInclude(typeof(Car))]
[XmlInclude(typeof(Tractor))]
public class Vehicle
{
	[XmlIgnore]
	public string Type => this.GetType().Name;
	
	[XmlAttribute("brand")]
	public string Brand { get; set; }
	
	[XmlAttribute("kg")]
	public int Weight { get; set; }
}

public class Truck : Vehicle
{
}

public class Car : Vehicle
{
}

public class Tractor : Vehicle
{
}

var cp = (Carpark)serializer.Deserialize(someStreamReader);

dotnetfiddle