获取与每个组相关联的最大值。

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英文:

Get the value associated with maximum per group

问题

I understand your request. Here's the translation of the text you provided:

我在处理一些非常简单的事情,但它让我发疯。我正在使用MySQL和PHPMyadmin。
基本上,我有一个包含URL、ID(唯一)和来源的表格。
每个来源有时会有多个URL。

我只想要每个来源的最长URL。

我有类似以下的东西:

pid source url
1 127 a-url
2 127 a-longer-url
3 128 some-kind-of-url
4 128 some-url

我试图显示:

pid source url
2 127 a-longer-url
3 128 some-kind-of-url

所以,只需获取每个来源的最长URL。

我一直在尝试类似以下的内容:

SELECT pid, source, MAX(LENGTH(url)), url FROM table GROUP BY source

但尽管它显示正确的最大长度数字,我无法获取正确的URL字符串,因为它显示的不是最长的那个。

非常感谢您的帮助。

英文:

I'm struggling on something very simple and it's making me crazy. I'm using MySQL and PHPMyadmin.
Basically, I have a table containing urls, ids (unique) and source.
Each source has sometime several urls.

I simply want to **longest url per source. **

I have something like this:

pid source url
1 127 a-url
2 127 a-longer-url
3 128 some-kind-of-url
4 128 some-url

And I'm trying to display:

pid source url
2 127 a-longer-url
3 128 some-kind-of-url

So, simply getting the longer url per source.

I've been trying stuff like:

SELECT pid, source, MAX(LENGTH(url)), url FROM table GROUP BY source

but though it displays the right maximum length in number I cannot fetch the right url string, as it displays another one than the longest.

Thanks a lot for your help.

答案1

得分: 0

你可以使用窗口函数来按照它们的url长度来排列具有相同source的行,然后选择每个组中的顶部行:

select *
from (
    select t.*, rank() over(partition by source order by char_length(url) desc) rn 
    from mytable t
) t
where rn = 1

这将返回顶部的并列项,如果有的话;否则,在窗口函数的order by子句中,你需要添加一个额外的排序条件。

英文:

You can use window functions to rank rows having the same source by the length of their url, then select the top row(s) per group:

select *
from (
    select t.*, rank() over(partition by source order by char_length(url) desc) rn 
    from mytable t
) t
where rn = 1

This returns top ties, if any; else, you would need an additional sorting criteria in the order by clause of the window function.

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  • 本文由 发表于 2023年6月21日 23:23:25
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