如何在PHP中替换两个字符之间的字符串值

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英文:

How to replace the value of a string within two characters in php

问题

早上好,大家,

我需要找出是否有一种方法可以更改 * * 内的值。

示例:

大家好,这是我的第一篇帖子。
*photo1*
*photo2*
*photo3*
很快见...

并将代码替换为:

大家好,这是我的第一篇帖子。
*photo*
*photo*
*photo*
很快见...

在单词 "photo" 后面没有数字

当前的工作方式:

我有一个包含在星号之间的单词 "photo1"、"photo2"、"photo3" 的文本文件。通过 file_get_contents 命令读取此文件,我需要删除单词 "photo" 末尾的数字。

英文:

Good morning everyone,
I need to figure out if there is a way to change the values inside the * *.

Example:

Hello everyone, this is my 1st post.
*photo1*
*photo2*
*photo3*
See you soon...

and replace the code with:

Hello everyone, this is my 1st post.
*photo*
*photo*
*photo*
See you soon...

without number after the word photo

How it works currently:

I have a txt file that contains the words photo1, photo2, photo3 between asterisks. This file is read via the file_get_contents command and I would need to remove the number at the end of the word photo.

答案1

得分: 1

你可以使用 preg_replace 来实现这个。例如:

$str = ''*photo9*';

echo preg_replace(''/\*photo[0-9]+\*/'', ''photo'', $str);

输出:

> photo

注意:\ 是为了转义表达式中的星号 *,因为没有转义它的话,它会具有特殊含义 - 你需要匹配字面上的星号。

这可能更简单(取决于你想要做什么):

echo preg_replace(''/\d/'', '''', $str);

注意:\d 代表数字,将匹配从 0-9 的数字。更简洁的等价表达式是 /[0-9]+/ - + 意味着必须是一个或多个字符是数字。

英文:

You can use preg_replace for that. E.g:

$str = '*photo9*';

echo preg_replace('/\*photo[0-9]+\*/', 'photo', $str);

Output:

> photo

Note. \ is to escape the asterisk * in the expression, because it has a special meaning without it – you need to match the literal asterisk.

This may be more simple (depending on what you are trying to do):

echo preg_replace('/\d/', '', $str);

Note. \d stands for digit, and will target numerals from 0-9. A more concise equivalent would be /[0-9]+/ – The + means "one or more" characters must be a digit.

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  • 本文由 发表于 2023年6月19日 17:23:45
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