使用相同的实体类返回JSON和XML

huangapple go评论55阅读模式
英文:

Returning JSON and XML using the same entity class

问题

以下是翻译好的部分:

我有这个控制器代码它返回 XML如何在实体类或控制器上添加最少的代码行或少量注解使其返回 JSON

@GetMapping(value = "/check", produces = MediaType.APPLICATION_XML_VALUE)
@ResponseBody
public ResponseEntity<Result> getWapiResult(@RequestParam String sn){
    return new ResponseEntity(
            wapiService.getWapiData(sn).getBody(),
            new HttpHeaders(),
            HttpStatus.OK);
}

这是实体类

@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
public class Result {

    private boolean complete;
    private int srcsize;

    private String urlpath;
}
英文:

I have this controller code that is returning XML , how can i make it return JSON with minimum line of code or just with few annotation on the entity class or the controller .

		@GetMapping(value = &quot;/check&quot;, produces = MediaType.APPLICATION_XML_VALUE)
		    @ResponseBody
		    public ResponseEntity&lt;Result&gt; getWapiResult(@RequestParam String sn){
		        return new ResponseEntity(
		                wapiService.getWapiData(sn).getBody(),
		                new HttpHeaders(),
		                HttpStatus.OK);
		    }

This is the entity class

		@XmlRootElement
		@XmlAccessorType(XmlAccessType.FIELD)
		public class Result {
		
		    private boolean complete;
		    private int srcsize;
		
		    private String urlpath;
		}

答案1

得分: 2

需要更改控制器生成的内容:

@GetMapping(value = "/check", produces = MediaType.APPLICATION_JSON_VALUE)
@ResponseBody
public ResponseEntity<Result> getWapiResult(@RequestParam String sn) {
    return new ResponseEntity(
            wapiService.getWapiData(sn).getBody(),
            new HttpHeaders(),
            HttpStatus.OK);
}

并且从实体中删除不必要的注解:

public class Result {
    private boolean complete;
    private int srcsize;
    private String urlpath;
}
英文:

You need to change what controller produces

@GetMapping(value = &quot;/check&quot;, produces = MediaType.APPLICATION_JSON_VALUE)
@ResponseBody
public ResponseEntity&lt;Result&gt; getWapiResult(@RequestParam String sn){
            return new ResponseEntity(
                    wapiService.getWapiData(sn).getBody(),
                    new HttpHeaders(),
                    HttpStatus.OK);
        }

And remove unnecessary annotations from Entity

    public class Result {
        private boolean complete;
        private int srcsize;
        private String urlpath;
    }

答案2

得分: 0

我猜测你的应用程序是使用Spring框架编写的。
在Controller中:@ResponseBody注解告诉控制器返回的对象会自动序列化为JSON并传递回HttpResponse对象。
所以,请只保留注解@ResponseBody。在@GetMapping中,只保留value。
@GetMapping(value = "/check")。
在实体类中:移除所有@XML注解。在Result类中保留一个无参数构造函数。
这将返回JSON作为ResponseBody。

英文:

I guess your application is in Spring.
On Controller: The @ResponseBody annotation tells the controller that the object returned is automatically serialized into JSON and passed back into the HttpResponse object.
So, keep annotation only @ResponseBody. In @Get Mapping, keep only value.
@GetMapping(value = "/check").
On Entity class: Remove all annotation of @XML. Keep a no-arg constructor in Result class.
This will return JSON as ResponseBody.

huangapple
  • 本文由 发表于 2023年6月19日 11:58:57
  • 转载请务必保留本文链接:https://go.coder-hub.com/76503537.html
匿名

发表评论

匿名网友

:?: :razz: :sad: :evil: :!: :smile: :oops: :grin: :eek: :shock: :???: :cool: :lol: :mad: :twisted: :roll: :wink: :idea: :arrow: :neutral: :cry: :mrgreen:

确定