Inner Join 帮助关于 PostgreSQL

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英文:

Inner Join Help on PostgreSQL

问题

我有以下的数据库关系和针对 PostgreSQL 的查询:

创建性别表:

create table gender(
    gender_id int primary key,
    gender char(10))

创建学生表:

create table student(
    student_id int primary key,
    first_name char(50) not null,
    last_name char(50) not null,
    gender_id int not null,
    constraint gender_fk foreign key(gender_id) references gender(gender_id))

插入性别数据:

insert into gender values(1, 'Male');
insert into gender values(2, 'Female');
insert into gender values(3, 'Other');

插入学生数据:

insert into student values(101, 'John', 'Smith', 1);
insert into student values(102, 'Sara', 'Bradford', 2);
insert into student values(103, 'Joseph', 'Brown', 1);
insert into student values(104, 'David', 'Lopez', 3);

如何创建一个内连接语句以检查学生的性别是否为 'Female'?

所有其他性别('Male' 和 'Other')将只有空值。我想要一个输出如下的内连接表:

SELECT s.student_id, s.first_name, s.last_name, g.gender
FROM student s
LEFT JOIN gender g ON s.gender_id = g.gender_id
WHERE g.gender = 'Female';

请注意,这个查询使用了左连接 (LEFT JOIN) 并且筛选出了性别为 'Female' 的学生。其他性别的学生将在性别列中具有空值。

英文:

I have the following database relationship and query for PostgreSQL below:

Inner Join 帮助关于 PostgreSQL

create table gender(
	gender_id int primary key,
	gender char(10))

create table student(
	student_id int primary key,
	first_name char(50) not null,
	last_name char(50) not null,
	gender_id int not null,
	constraint gender_fk foreign key(gender_id) references gender(gender_id))

insert into gender values(1, 'Male');
insert into gender values(2, 'Female');
insert into gender values(3, 'Other');
insert into student values(101, 'John', 'Smith', 1);
insert into student values(102, 'Sara', 'Bradford', 2);
insert into student values(103, 'Joseph', 'Brown', 1);
insert into student values(104, 'David', 'Lopez', 3);

TABLE Student: Inner Join 帮助关于 PostgreSQL

TABLE Gender: Inner Join 帮助关于 PostgreSQL

How do I create an inner join statement that checks if the student's gender is 'Female'?

All other genders ('Male' and 'Other') will just have null value. I want an output like the following inner-joined table:

Inner Join 帮助关于 PostgreSQL

答案1

得分: 3

不需要涉及gender表:

SELECT student_id, first_name || ' ' || last_name AS full_name
     , CASE WHEN gender_id = 2 THEN 'Female' END AS chk_female
FROM   student;

SQL CASE 默认情况下返回 null,当缺少 ELSE 部分时。

如果坚持要进行连接操作,最好使用 LEFT [OUTER] JOIN 并在连接条件中筛选出 'Female'。然后,所有其他性别都会自动默认为 null

SELECT s.student_id, s.first_name || ' ' || s.last_name AS full_name
     , g.gender AS chk_female
FROM   student s
LEFT   JOIN gender g ON g.gender_id = s.gender_id AND g.gender = 'Female';

fiddle

第二个查询适用于gender_id的值不容易知道的情况,或者'Female'实际上是一个变量。

由于first_namelast_name都是NOT NULL,因此普通的连接操作是可以的。否则,可以考虑使用concat_ws()进行空安全的连接。参考:

另外:您不应该使用数据类型 char(n)。参考:

英文:

We don't even need to involve the gender table:

SELECT student_id, first_name || ' ' || last_name AS full_name
     , CASE WHEN gender_id = 2 THEN 'Female' END AS chk_female
FROM   student;

SQL CASE defaults to null, when the ELSE part is missing.

If you insist on a join, rather use LEFT [OUTER] JOIN and filter for 'Female' in the join condition. Then all other genders default to null automatically.:

SELECT s.student_id, s.first_name || ' ' || s.last_name AS full_name
     , g.gender AS chk_female
FROM   student s
LEFT   JOIN gender g ON g.gender_id = s.gender_id AND g.gender = 'Female';

fiddle

This second query is for situations where the gender_id of 'Female' is not readily known already, or 'Female' is really a variable.

Since both first_name and last_name are NOT NULL, plain concatenation is fine. else consider null-safe concatenation with concat_ws(). See:

Aside: you do not want to use the data type char(n). See:

答案2

得分: 0

不需要使用 JOIN 进行这个操作,但如果你要使用的话,我建议使用 OUTER JOIN 而不是 INNER JOIN。请参考这个链接:

https://dbfiddle.uk/YBzEtnOv

英文:

You don't need a JOIN for this, but if you were to use one I would suggest an OUTER join instead of INNER. See this:

> https://dbfiddle.uk/YBzEtnOv

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  • 本文由 发表于 2023年6月19日 10:09:27
  • 转载请务必保留本文链接:https://go.coder-hub.com/76503240.html
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